Discussion:
Distorted Sine Wave
(too old to reply)
Cursitor Doom
2024-05-29 17:07:25 UTC
Permalink
Gentlemen,

Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I was
building and in the process of trying to iron out the wrinkles of and
certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?

https://disk.yandex.com/i/z6fYbeVfPRK7aA
john larkin
2024-05-29 19:24:47 UTC
Permalink
On Wed, 29 May 2024 17:07:25 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I was
building and in the process of trying to iron out the wrinkles of and
certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Lots of 2nd harmonic. Got a schematic of the clock generator?

If so, where are you probing?
Arie de Muijnck
2024-05-29 19:43:54 UTC
Permalink
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I was
building and in the process of trying to iron out the wrinkles of and
certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.

Arie
john larkin
2024-05-29 20:42:13 UTC
Permalink
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I was
building and in the process of trying to iron out the wrinkles of and
certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.

Our boxes output a 10 MHz square wave. Our clock inputs have a 10 MHz
bandpass filter, so they accept most anything.
Cursitor Doom
2024-05-29 20:49:27 UTC
Permalink
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
Post by john larkin
Our boxes output a 10 MHz square wave. Our clock inputs have a 10 MHz
bandpass filter, so they accept most anything.
Joe Gwinn
2024-05-29 21:05:50 UTC
Permalink
On Wed, 29 May 2024 20:49:27 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
What is the nature of the load?

Joe Gwinn
Jeroen Belleman
2024-05-29 21:10:56 UTC
Permalink
Post by Cursitor Doom
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
If this oscillator is made to drive 50 Ohms and you don't
provide that, internal buffer stages may saturate or do other
weird things. If it works OK *with* the 50 Ohm load, then
your problem is solved, no?

Jeroen Belleman
Cursitor Doom
2024-05-29 21:54:32 UTC
Permalink
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found
the 10Mhz reference oscillator is generating an 'unsatisfactory
waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators
I was building and in the process of trying to iron out the wrinkles
of and certainly NOT a critical reference oscillator from a
respected manufacturer. Can anyone tell what's most likely going on
here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe
cable's only 4' long! However, with the 50 ohm input enabled, the 2nd
harmonic disappears. It's just one of those inexplicable mysteries that
no one knows the answer to. :)
If this oscillator is made to drive 50 Ohms and you don't provide that,
internal buffer stages may saturate or do other weird things. If it
works OK *with* the 50 Ohm load, then your problem is solved, no?
Jeroen Belleman
Unfortunately not. the suspicion that there was something wrong with that
oscillator was my main hope of an easy fix for this analyzer. Now I have
to go back to the drawing board and start trouble-shooting all over again.
And it's a complex beast!
Phil Hobbs
2024-05-29 22:11:47 UTC
Permalink
Post by Cursitor Doom
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
That’s pretty diagnostic. There must be an LC filter on the
output—mis-terminating it will cause all sorts of frequency-response
whoopdedoos.

Cheers

Phil Hobbs
--
Dr Philip C D Hobbs Principal Consultant ElectroOptical Innovations LLC /
Hobbs ElectroOptics Optics, Electro-optics, Photonics, Analog Electronics
Joe Gwinn
2024-05-29 22:59:39 UTC
Permalink
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
That’s pretty diagnostic. There must be an LC filter on the
output—mis-terminating it will cause all sorts of frequency-response
whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may be 50
ohms for positive input voltage, and say 10 Kohm for negative. At the
very least one could get an inverted reflection on negative.

Joe Gwinn
Phil Hobbs
2024-05-30 19:02:44 UTC
Permalink
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Phil Hobbs
Post by Cursitor Doom
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
That’s pretty diagnostic. There must be an LC filter on the
output—mis-terminating it will cause all sorts of frequency-response
whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may be 50
ohms for positive input voltage, and say 10 Kohm for negative. At the
very least one could get an inverted reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.

Cheers

Phil Hobbs
--
Dr Philip C D Hobbs
Principal Consultant
ElectroOptical Innovations LLC / Hobbs ElectroOptics
Optics, Electro-optics, Photonics, Analog Electronics
Briarcliff Manor NY 10510

http://electrooptical.net
http://hobbs-eo.com
Joe Gwinn
2024-05-30 20:06:47 UTC
Permalink
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
That’s pretty diagnostic. There must be an LC filter on the
output—mis-terminating it will cause all sorts of frequency-response
whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may be 50
ohms for positive input voltage, and say 10 Kohm for negative. At the
very least one could get an inverted reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.

I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must be
elsewhere. Or, it's just busted.

.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://xdevs.com/doc/HP_Agilent_Keysight/HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>

Joe Gwinn
john larkin
2024-05-30 21:56:30 UTC
Permalink
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
That’s pretty diagnostic. There must be an LC filter on the
output—mis-terminating it will cause all sorts of frequency-response
whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may be 50
ohms for positive input voltage, and say 10 Kohm for negative. At the
very least one could get an inverted reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must be
elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://xdevs.com/doc/HP_Agilent_Keysight/HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Joe Gwinn
334 pages! Where is the issue?
Joe Gwinn
2024-05-30 22:53:29 UTC
Permalink
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
That’s pretty diagnostic. There must be an LC filter on the
output—mis-terminating it will cause all sorts of frequency-response
whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may be 50
ohms for positive input voltage, and say 10 Kohm for negative. At the
very least one could get an inverted reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must be
elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://xdevs.com/doc/HP_Agilent_Keysight/HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I found
it was to look at the schematics. Look for module A22. Don't think
search works on such images, but visual search didn't take that long.

Joe Gwinn
john larkin
2024-05-30 23:24:25 UTC
Permalink
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
That’s pretty diagnostic. There must be an LC filter on the
output—mis-terminating it will cause all sorts of frequency-response
whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may be 50
ohms for positive input voltage, and say 10 Kohm for negative. At the
very least one could get an inverted reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must be
elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://xdevs.com/doc/HP_Agilent_Keysight/HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I found
it was to look at the schematics. Look for module A22. Don't think
search works on such images, but visual search didn't take that long.
Joe Gwinn
Too much work for free consulting.
Joe Gwinn
2024-05-31 15:34:46 UTC
Permalink
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
That’s pretty diagnostic. There must be an LC filter on the
output—mis-terminating it will cause all sorts of frequency-response
whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may be 50
ohms for positive input voltage, and say 10 Kohm for negative. At the
very least one could get an inverted reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must be
elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://xdevs.com/doc/HP_Agilent_Keysight/HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I found
it was to look at the schematics. Look for module A22. Don't think
search works on such images, but visual search didn't take that long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge,
near the bottom, which is not marked as a page X of Y, but is.

Anyway, look at pages 59 and 77. At 77, look for A22 in the lower
left region. Just above, look for INT and EXT jacks. The EXT jack is
where an external reference enters.

Joe Gwinn
Cursitor Doom
2024-05-31 17:29:47 UTC
Permalink
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've
found the 10Mhz reference oscillator is generating an
'unsatisfactory waveform'
which may be causing the device to be unable to lock it's
main PLL. I've come across this waveshape before, but mostly
with oscillators I was building and in the process of trying
to iron out the wrinkles of and certainly NOT a critical
reference oscillator from a respected manufacturer. Can
anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm
termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of those
inexplicable mysteries that no one knows the answer to. :)
That’s pretty diagnostic. There must be an LC filter on the
output—mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may
be 50 ohms for positive input voltage, and say 10 Kohm for
negative. At the very least one could get an inverted reflection
on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must be
elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I found
it was to look at the schematics. Look for module A22. Don't think
search works on such images, but visual search didn't take that long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge, near
the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower left
region. Just above, look for INT and EXT jacks. The EXT jack is where
an external reference enters.
Joe Gwinn
I don't believe the 10Mhz ref osc is the problem, John. The 2nd harmonic
distortion goes away when the scope input impedance is set to 50 ohms.
There is some slight distortion on it, but not enough to cause an out-of-
lock error. Furthermore, since that osc is the pace-setter for every other
module in every other loop in this analyzer, its failure would give rise
to way more error messages than a mere "YTO unlock" as it stands at
present. The manual suggests the most likely areas where the fault is
located are in one of the boards A19, A20, A21 or A11. If A22 were the
culprit, there would be over a dozen error messages.
Joe Gwinn
2024-05-31 18:48:28 UTC
Permalink
On Fri, 31 May 2024 17:29:47 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've
found the 10Mhz reference oscillator is generating an
'unsatisfactory waveform'
which may be causing the device to be unable to lock it's
main PLL. I've come across this waveshape before, but mostly
with oscillators I was building and in the process of trying
to iron out the wrinkles of and certainly NOT a critical
reference oscillator from a respected manufacturer. Can
anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm
termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of those
inexplicable mysteries that no one knows the answer to. :)
That?s pretty diagnostic. There must be an LC filter on the
output?mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may
be 50 ohms for positive input voltage, and say 10 Kohm for
negative. At the very least one could get an inverted reflection
on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must be
elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I found
it was to look at the schematics. Look for module A22. Don't think
search works on such images, but visual search didn't take that long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge, near
the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower left
region. Just above, look for INT and EXT jacks. The EXT jack is where
an external reference enters.
Joe Gwinn
I don't believe the 10Mhz ref osc is the problem, John. The 2nd harmonic
distortion goes away when the scope input impedance is set to 50 ohms.
There is some slight distortion on it, but not enough to cause an out-of-
lock error. Furthermore, since that osc is the pace-setter for every other
module in every other loop in this analyzer, its failure would give rise
to way more error messages than a mere "YTO unlock" as it stands at
present. The manual suggests the most likely areas where the fault is
located are in one of the boards A19, A20, A21 or A11. If A22 were the
culprit, there would be over a dozen error messages.
What is the 10 MHz signal power level at the EXT input in these two
castes, 1 Mohm and 50 Ohm? The expected range is 0 to +10 dBm.

Joe Gwinn
Cursitor Doom
2024-05-31 22:17:37 UTC
Permalink
Post by Joe Gwinn
On Fri, 31 May 2024 17:29:47 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've
found the 10Mhz reference oscillator is generating an
'unsatisfactory waveform'
which may be causing the device to be unable to lock it's
main PLL. I've come across this waveshape before, but
mostly with oscillators I was building and in the process
of trying to iron out the wrinkles of and certainly NOT a
critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd
harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of those
inexplicable mysteries that no one knows the answer to. :)
That?s pretty diagnostic. There must be an LC filter on the
output?mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may
be 50 ohms for positive input voltage, and say 10 Kohm for
negative. At the very least one could get an inverted
reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must be
elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I
found it was to look at the schematics. Look for module A22. Don't
think search works on such images, but visual search didn't take that
long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge,
near the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower
left region. Just above, look for INT and EXT jacks. The EXT jack is
where an external reference enters.
Joe Gwinn
I don't believe the 10Mhz ref osc is the problem, John. The 2nd harmonic
distortion goes away when the scope input impedance is set to 50 ohms.
There is some slight distortion on it, but not enough to cause an
out-of- lock error. Furthermore, since that osc is the pace-setter for
every other module in every other loop in this analyzer, its failure
would give rise to way more error messages than a mere "YTO unlock" as
it stands at present. The manual suggests the most likely areas where
the fault is located are in one of the boards A19, A20, A21 or A11. If
A22 were the culprit, there would be over a dozen error messages.
What is the 10 MHz signal power level at the EXT input in these two
castes, 1 Mohm and 50 Ohm? The expected range is 0 to +10 dBm.
Joe Gwinn
7.68dBm on 50 Ohms
2.68V P-P on 1 Meg

No issues there AFAIC.
Cursitor Doom
2024-06-01 00:04:27 UTC
Permalink
Post by Joe Gwinn
On Fri, 31 May 2024 17:29:47 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 16:06:47 -0400, Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer,
I've found the 10Mhz reference oscillator is generating an
'unsatisfactory waveform'
which may be causing the device to be unable to lock it's
main PLL. I've come across this waveshape before, but
mostly with oscillators I was building and in the process
of trying to iron out the wrinkles of and certainly NOT a
critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd
harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of those
inexplicable mysteries that no one knows the answer to. :)
That?s pretty diagnostic. There must be an LC filter on the
output?mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax
may be 50 ohms for positive input voltage, and say 10 Kohm for
negative. At the very least one could get an inverted
reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must
be elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I
found it was to look at the schematics. Look for module A22. Don't
think search works on such images, but visual search didn't take
that long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge,
near the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower
left region. Just above, look for INT and EXT jacks. The EXT jack
is where an external reference enters.
Joe Gwinn
I don't believe the 10Mhz ref osc is the problem, John. The 2nd
harmonic distortion goes away when the scope input impedance is set to
50 ohms. There is some slight distortion on it, but not enough to cause
an out-of- lock error. Furthermore, since that osc is the pace-setter
for every other module in every other loop in this analyzer, its
failure would give rise to way more error messages than a mere "YTO
unlock" as it stands at present. The manual suggests the most likely
areas where the fault is located are in one of the boards A19, A20, A21
or A11. If A22 were the culprit, there would be over a dozen error
messages.
What is the 10 MHz signal power level at the EXT input in these two
castes, 1 Mohm and 50 Ohm? The expected range is 0 to +10 dBm.
Joe Gwinn
7.68dBm on 50 Ohms 2.68V P-P on 1 Meg
No issues there AFAIC.
Except for some distortion. I'd have expected better spectral purity from
a xtal reference oscillator. Perhaps I should try a different scope just
to be sure it's not that that's at fault...
Joe Gwinn
2024-06-01 18:28:35 UTC
Permalink
On Fri, 31 May 2024 22:17:37 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by Joe Gwinn
On Fri, 31 May 2024 17:29:47 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've
found the 10Mhz reference oscillator is generating an
'unsatisfactory waveform'
which may be causing the device to be unable to lock it's
main PLL. I've come across this waveshape before, but
mostly with oscillators I was building and in the process
of trying to iron out the wrinkles of and certainly NOT a
critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd
harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of those
inexplicable mysteries that no one knows the answer to. :)
That?s pretty diagnostic. There must be an LC filter on the
output?mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may
be 50 ohms for positive input voltage, and say 10 Kohm for
negative. At the very least one could get an inverted
reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must be
elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I
found it was to look at the schematics. Look for module A22. Don't
think search works on such images, but visual search didn't take that
long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge,
near the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower
left region. Just above, look for INT and EXT jacks. The EXT jack is
where an external reference enters.
Joe Gwinn
I don't believe the 10Mhz ref osc is the problem, John. The 2nd harmonic
distortion goes away when the scope input impedance is set to 50 ohms.
There is some slight distortion on it, but not enough to cause an
out-of- lock error. Furthermore, since that osc is the pace-setter for
every other module in every other loop in this analyzer, its failure
would give rise to way more error messages than a mere "YTO unlock" as
it stands at present. The manual suggests the most likely areas where
the fault is located are in one of the boards A19, A20, A21 or A11. If
A22 were the culprit, there would be over a dozen error messages.
What is the 10 MHz signal power level at the EXT input in these two
castes, 1 Mohm and 50 Ohm? The expected range is 0 to +10 dBm.
Joe Gwinn
7.68dBm on 50 Ohms
2.68V P-P on 1 Meg
No issues there AFAIC.
Not so fast there. It's the scope that is being set to 1 Meg or 50
ohm, and at 1 Meg we are observing the drive into the 50 ohm input
impedance of the EXT ref input of the spectrum analyzer.

That 2.7 Vpp over 50 ohms is about +13 dBm, which exceeds +10 dBm. So
the EXT input may be over-driven. Install a 5-dB inline attenuator and
see what happens.

Joe Gwinn
Cursitor Doom
2024-06-01 19:21:29 UTC
Permalink
Post by Joe Gwinn
On Fri, 31 May 2024 22:17:37 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
On Fri, 31 May 2024 17:29:47 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 16:06:47 -0400, Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer,
I've found the 10Mhz reference oscillator is generating
an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's
main PLL. I've come across this waveshape before, but
mostly with oscillators I was building and in the process
of trying to iron out the wrinkles of and certainly NOT a
critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on
here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm
termination.
Arie
If the drive is a sine wave, a cable can't generate that
2nd harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of those
inexplicable mysteries that no one knows the answer to. :)
That?s pretty diagnostic. There must be an LC filter on the
output?mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax
may be 50 ohms for positive input voltage, and say 10 Kohm for
negative. At the very least one could get an inverted
reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must
be elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I
found it was to look at the schematics. Look for module A22.
Don't think search works on such images, but visual search didn't
take that long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge,
near the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower
left region. Just above, look for INT and EXT jacks. The EXT jack
is where an external reference enters.
Joe Gwinn
I don't believe the 10Mhz ref osc is the problem, John. The 2nd
harmonic distortion goes away when the scope input impedance is set to
50 ohms. There is some slight distortion on it, but not enough to
cause an out-of- lock error. Furthermore, since that osc is the
pace-setter for every other module in every other loop in this
analyzer, its failure would give rise to way more error messages than
a mere "YTO unlock" as it stands at present. The manual suggests the
most likely areas where the fault is located are in one of the boards
A19, A20, A21 or A11. If A22 were the culprit, there would be over a
dozen error messages.
What is the 10 MHz signal power level at the EXT input in these two
castes, 1 Mohm and 50 Ohm? The expected range is 0 to +10 dBm.
Joe Gwinn
7.68dBm on 50 Ohms 2.68V P-P on 1 Meg
No issues there AFAIC.
Not so fast there. It's the scope that is being set to 1 Meg or 50 ohm,
and at 1 Meg we are observing the drive into the 50 ohm input impedance
of the EXT ref input of the spectrum analyzer.
Unless I misunderstand what you're saying, that's not the case, though.
What we are observing is the output of the analyzer's 10Mhz reference
oscillator taken from a BNC socket on the rear of it which HP have
thoughtfully provided and fed directly into a scope switchable between 1M
and 50 Ohms.
Post by Joe Gwinn
That 2.7 Vpp over 50 ohms is about +13 dBm, which exceeds +10 dBm. So
the EXT input may be over-driven. Install a 5-dB inline attenuator and
see what happens.
It's not an external input. They've put it there in order to make it easy
to check the frequency of the reference oscillator and adjust it to
precisely 10.000000Mhz if necessary (after a *minimum* 72 hour warm-up!)
Joe Gwinn
2024-06-01 21:18:03 UTC
Permalink
On Sat, 1 Jun 2024 19:21:29 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by Joe Gwinn
On Fri, 31 May 2024 22:17:37 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
On Fri, 31 May 2024 17:29:47 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 16:06:47 -0400, Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer,
I've found the 10Mhz reference oscillator is generating
an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's
main PLL. I've come across this waveshape before, but
mostly with oscillators I was building and in the process
of trying to iron out the wrinkles of and certainly NOT a
critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on
here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm
termination.
Arie
If the drive is a sine wave, a cable can't generate that
2nd harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of those
inexplicable mysteries that no one knows the answer to. :)
That?s pretty diagnostic. There must be an LC filter on the
output?mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax
may be 50 ohms for positive input voltage, and say 10 Kohm for
negative. At the very least one could get an inverted
reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must
be elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I
found it was to look at the schematics. Look for module A22.
Don't think search works on such images, but visual search didn't
take that long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge,
near the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower
left region. Just above, look for INT and EXT jacks. The EXT jack
is where an external reference enters.
Joe Gwinn
I don't believe the 10Mhz ref osc is the problem, John. The 2nd
harmonic distortion goes away when the scope input impedance is set to
50 ohms. There is some slight distortion on it, but not enough to
cause an out-of- lock error. Furthermore, since that osc is the
pace-setter for every other module in every other loop in this
analyzer, its failure would give rise to way more error messages than
a mere "YTO unlock" as it stands at present. The manual suggests the
most likely areas where the fault is located are in one of the boards
A19, A20, A21 or A11. If A22 were the culprit, there would be over a
dozen error messages.
What is the 10 MHz signal power level at the EXT input in these two
castes, 1 Mohm and 50 Ohm? The expected range is 0 to +10 dBm.
Joe Gwinn
7.68dBm on 50 Ohms 2.68V P-P on 1 Meg
No issues there AFAIC.
Not so fast there. It's the scope that is being set to 1 Meg or 50 ohm,
and at 1 Meg we are observing the drive into the 50 ohm input impedance
of the EXT ref input of the spectrum analyzer.
Unless I misunderstand what you're saying, that's not the case, though.
What we are observing is the output of the analyzer's 10Mhz reference
oscillator taken from a BNC socket on the rear of it which HP have
thoughtfully provided and fed directly into a scope switchable between 1M
and 50 Ohms.
Post by Joe Gwinn
That 2.7 Vpp over 50 ohms is about +13 dBm, which exceeds +10 dBm. So
the EXT input may be over-driven. Install a 5-dB inline attenuator and
see what happens.
It's not an external input. They've put it there in order to make it easy
to check the frequency of the reference oscillator and adjust it to
precisely 10.000000Mhz if necessary (after a *minimum* 72 hour warm-up!)
Maybe. But it's simpler to just try the attenuator.

Joe Gwinn
Cursitor Doom
2024-06-01 21:46:10 UTC
Permalink
Post by Joe Gwinn
On Sat, 1 Jun 2024 19:21:29 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by Joe Gwinn
On Fri, 31 May 2024 22:17:37 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
On Fri, 31 May 2024 17:29:47 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 18:53:29 -0400, Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 16:06:47 -0400, Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer,
I've found the 10Mhz reference oscillator is generating
an 'unsatisfactory waveform'
which may be causing the device to be unable to lock
it's main PLL. I've come across this waveshape before,
but mostly with oscillators I was building and in the
process of trying to iron out the wrinkles of and
certainly NOT a critical reference oscillator from a
respected manufacturer. Can anyone tell what's most
likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm
termination.
Arie
If the drive is a sine wave, a cable can't generate that
2nd harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of
those inexplicable mysteries that no one knows the answer
to. :)
That?s pretty diagnostic. There must be an LC filter on the
output?mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with
a resistor somewhere, the impedance presented to the feed
coax may be 50 ohms for positive input voltage, and say 10
Kohm for negative. At the very least one could get an
inverted reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem
must be elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by Joe Gwinn
Post by Joe Gwinn
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I
found it was to look at the schematics. Look for module A22.
Don't think search works on such images, but visual search didn't
take that long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge,
near the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower
left region. Just above, look for INT and EXT jacks. The EXT
jack is where an external reference enters.
Joe Gwinn
I don't believe the 10Mhz ref osc is the problem, John. The 2nd
harmonic distortion goes away when the scope input impedance is set
to 50 ohms. There is some slight distortion on it, but not enough to
cause an out-of- lock error. Furthermore, since that osc is the
pace-setter for every other module in every other loop in this
analyzer, its failure would give rise to way more error messages
than a mere "YTO unlock" as it stands at present. The manual
suggests the most likely areas where the fault is located are in one
of the boards A19, A20, A21 or A11. If A22 were the culprit, there
would be over a dozen error messages.
What is the 10 MHz signal power level at the EXT input in these two
castes, 1 Mohm and 50 Ohm? The expected range is 0 to +10 dBm.
Joe Gwinn
7.68dBm on 50 Ohms 2.68V P-P on 1 Meg
No issues there AFAIC.
Not so fast there. It's the scope that is being set to 1 Meg or 50 ohm,
and at 1 Meg we are observing the drive into the 50 ohm input
impedance of the EXT ref input of the spectrum analyzer.
Unless I misunderstand what you're saying, that's not the case, though.
What we are observing is the output of the analyzer's 10Mhz reference
oscillator taken from a BNC socket on the rear of it which HP have
thoughtfully provided and fed directly into a scope switchable between
1M and 50 Ohms.
Post by Joe Gwinn
That 2.7 Vpp over 50 ohms is about +13 dBm, which exceeds +10 dBm. So
the EXT input may be over-driven. Install a 5-dB inline attenuator and
see what happens.
It's not an external input. They've put it there in order to make it
easy to check the frequency of the reference oscillator and adjust it to
precisely 10.000000Mhz if necessary (after a *minimum* 72 hour warm-up!)
Maybe. But it's simpler to just try the attenuator.
Joe Gwinn
If I can find a reverse attenuator, I'd be happy to try it.
Joe Gwinn
2024-06-01 22:03:01 UTC
Permalink
On Sat, 1 Jun 2024 21:46:10 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by Joe Gwinn
On Sat, 1 Jun 2024 19:21:29 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by Joe Gwinn
On Fri, 31 May 2024 22:17:37 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
On Fri, 31 May 2024 17:29:47 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 18:53:29 -0400, Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 16:06:47 -0400, Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer,
I've found the 10Mhz reference oscillator is generating
an 'unsatisfactory waveform'
which may be causing the device to be unable to lock
it's main PLL. I've come across this waveshape before,
but mostly with oscillators I was building and in the
process of trying to iron out the wrinkles of and
certainly NOT a critical reference oscillator from a
respected manufacturer. Can anyone tell what's most
likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm
termination.
Arie
If the drive is a sine wave, a cable can't generate that
2nd harmonic.
I don't understand how a reflection can account for it
either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of
those inexplicable mysteries that no one knows the answer
to. :)
That?s pretty diagnostic. There must be an LC filter on the
output?mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with
a resistor somewhere, the impedance presented to the feed
coax may be 50 ohms for positive input voltage, and say 10
Kohm for negative. At the very least one could get an
inverted reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem
must be elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by Joe Gwinn
Post by Joe Gwinn
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I
found it was to look at the schematics. Look for module A22.
Don't think search works on such images, but visual search didn't
take that long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge,
near the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower
left region. Just above, look for INT and EXT jacks. The EXT
jack is where an external reference enters.
Joe Gwinn
I don't believe the 10Mhz ref osc is the problem, John. The 2nd
harmonic distortion goes away when the scope input impedance is set
to 50 ohms. There is some slight distortion on it, but not enough to
cause an out-of- lock error. Furthermore, since that osc is the
pace-setter for every other module in every other loop in this
analyzer, its failure would give rise to way more error messages
than a mere "YTO unlock" as it stands at present. The manual
suggests the most likely areas where the fault is located are in one
of the boards A19, A20, A21 or A11. If A22 were the culprit, there
would be over a dozen error messages.
What is the 10 MHz signal power level at the EXT input in these two
castes, 1 Mohm and 50 Ohm? The expected range is 0 to +10 dBm.
Joe Gwinn
7.68dBm on 50 Ohms 2.68V P-P on 1 Meg
No issues there AFAIC.
Not so fast there. It's the scope that is being set to 1 Meg or 50 ohm,
and at 1 Meg we are observing the drive into the 50 ohm input
impedance of the EXT ref input of the spectrum analyzer.
Unless I misunderstand what you're saying, that's not the case, though.
What we are observing is the output of the analyzer's 10Mhz reference
oscillator taken from a BNC socket on the rear of it which HP have
thoughtfully provided and fed directly into a scope switchable between
1M and 50 Ohms.
Post by Joe Gwinn
That 2.7 Vpp over 50 ohms is about +13 dBm, which exceeds +10 dBm. So
the EXT input may be over-driven. Install a 5-dB inline attenuator and
see what happens.
It's not an external input. They've put it there in order to make it
easy to check the frequency of the reference oscillator and adjust it to
precisely 10.000000Mhz if necessary (after a *minimum* 72 hour warm-up!)
Maybe. But it's simpler to just try the attenuator.
Joe Gwinn
If I can find a reverse attenuator, I'd be happy to try it.
I don't think you need such a thing. Inline attenuators (male-female)
are symmetric, and don't care which way the signal travels.

Joe Gwinn
Cursitor Doom
2024-05-31 18:54:06 UTC
Permalink
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've
found the 10Mhz reference oscillator is generating an
'unsatisfactory waveform'
which may be causing the device to be unable to lock it's
main PLL. I've come across this waveshape before, but mostly
with oscillators I was building and in the process of trying
to iron out the wrinkles of and certainly NOT a critical
reference oscillator from a respected manufacturer. Can
anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm
termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of those
inexplicable mysteries that no one knows the answer to. :)
That’s pretty diagnostic. There must be an LC filter on the
output—mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may
be 50 ohms for positive input voltage, and say 10 Kohm for
negative. At the very least one could get an inverted reflection
on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must be
elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I found
it was to look at the schematics. Look for module A22. Don't think
search works on such images, but visual search didn't take that long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge, near
the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower left
region. Just above, look for INT and EXT jacks. The EXT jack is where
an external reference enters.
Joe Gwinn
It's just a block diagram of the reference oscillator module. There's no
detailed schematic of the oscillator itself. At least that's the case with
the PDF version of the Service Manual I have.
Joe Gwinn
2024-05-31 19:10:32 UTC
Permalink
On Fri, 31 May 2024 18:54:06 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've
found the 10Mhz reference oscillator is generating an
'unsatisfactory waveform'
which may be causing the device to be unable to lock it's
main PLL. I've come across this waveshape before, but mostly
with oscillators I was building and in the process of trying
to iron out the wrinkles of and certainly NOT a critical
reference oscillator from a respected manufacturer. Can
anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm
termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of those
inexplicable mysteries that no one knows the answer to. :)
That?s pretty diagnostic. There must be an LC filter on the
output?mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may
be 50 ohms for positive input voltage, and say 10 Kohm for
negative. At the very least one could get an inverted reflection
on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must be
elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I found
it was to look at the schematics. Look for module A22. Don't think
search works on such images, but visual search didn't take that long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge, near
the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower left
region. Just above, look for INT and EXT jacks. The EXT jack is where
an external reference enters.
Joe Gwinn
It's just a block diagram of the reference oscillator module. There's no
detailed schematic of the oscillator itself. At least that's the case with
the PDF version of the Service Manual I have.
It's probably in the book that I don't have, if it was ever released.

Joe Gwinn
Cursitor Doom
2024-05-31 21:40:04 UTC
Permalink
Post by Joe Gwinn
On Fri, 31 May 2024 18:54:06 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've
found the 10Mhz reference oscillator is generating an
'unsatisfactory waveform'
which may be causing the device to be unable to lock it's
main PLL. I've come across this waveshape before, but
mostly with oscillators I was building and in the process
of trying to iron out the wrinkles of and certainly NOT a
critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd
harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of those
inexplicable mysteries that no one knows the answer to. :)
That?s pretty diagnostic. There must be an LC filter on the
output?mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may
be 50 ohms for positive input voltage, and say 10 Kohm for
negative. At the very least one could get an inverted
reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must be
elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I
found it was to look at the schematics. Look for module A22. Don't
think search works on such images, but visual search didn't take that
long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge,
near the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower
left region. Just above, look for INT and EXT jacks. The EXT jack is
where an external reference enters.
Joe Gwinn
It's just a block diagram of the reference oscillator module. There's no
detailed schematic of the oscillator itself. At least that's the case
with the PDF version of the Service Manual I have.
It's probably in the book that I don't have, if it was ever released.
Joe Gwinn
HP actually published at least 5 manuals of various kinds about this
analyzer, so it's possible it's in one of the others. However, the actual
service manual is where I'd expect to find it if they published it at all.
The other titles are:

HP 8566B Operator's Manual
HP 8566B Installation and Verification Manual
HP 8566B Test and Adjustments Manual
HP 8566B Troubleshooting and Repair Manual

So if the answers are not in *any* of the above, it'd be jolly rotten luck
indeed!
boB
2024-06-01 00:02:13 UTC
Permalink
On Fri, 31 May 2024 21:40:04 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by Joe Gwinn
On Fri, 31 May 2024 18:54:06 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've
found the 10Mhz reference oscillator is generating an
'unsatisfactory waveform'
which may be causing the device to be unable to lock it's
main PLL. I've come across this waveshape before, but
mostly with oscillators I was building and in the process
of trying to iron out the wrinkles of and certainly NOT a
critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd
harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of those
inexplicable mysteries that no one knows the answer to. :)
That?s pretty diagnostic. There must be an LC filter on the
output?mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may
be 50 ohms for positive input voltage, and say 10 Kohm for
negative. At the very least one could get an inverted
reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must be
elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I
found it was to look at the schematics. Look for module A22. Don't
think search works on such images, but visual search didn't take that
long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge,
near the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower
left region. Just above, look for INT and EXT jacks. The EXT jack is
where an external reference enters.
Joe Gwinn
It's just a block diagram of the reference oscillator module. There's no
detailed schematic of the oscillator itself. At least that's the case
with the PDF version of the Service Manual I have.
It's probably in the book that I don't have, if it was ever released.
Joe Gwinn
HP actually published at least 5 manuals of various kinds about this
analyzer, so it's possible it's in one of the others. However, the actual
service manual is where I'd expect to find it if they published it at all.
HP 8566B Operator's Manual
HP 8566B Installation and Verification Manual
HP 8566B Test and Adjustments Manual
HP 8566B Troubleshooting and Repair Manual
So if the answers are not in *any* of the above, it'd be jolly rotten luck
indeed!
Looking at that waveform again...

Could it be that the wavform you are seeing there is not a harmonic
but just a partial cancelation due to reflections ?

If you look at one peak vs. the other, they look about the same time
to me. About 1 scope division. Just the amplitude looks different on
alternating cycles. A non-linearity I would think would make an even
harmonic. 2nd harmonic is usually due to non 1/2 wave symetry (DC
offset bascially)

What was tha amplitude after you loaded it down properly ? How about
a picture ?

Where were you scoping this at again ?

boB
boB
2024-06-01 00:33:51 UTC
Permalink
Post by boB
On Fri, 31 May 2024 21:40:04 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by Joe Gwinn
On Fri, 31 May 2024 18:54:06 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've
found the 10Mhz reference oscillator is generating an
'unsatisfactory waveform'
which may be causing the device to be unable to lock it's
main PLL. I've come across this waveshape before, but
mostly with oscillators I was building and in the process
of trying to iron out the wrinkles of and certainly NOT a
critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on
here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm
termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd
harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of those
inexplicable mysteries that no one knows the answer to. :)
That?s pretty diagnostic. There must be an LC filter on the
output?mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with a
resistor somewhere, the impedance presented to the feed coax may
be 50 ohms for positive input voltage, and say 10 Kohm for
negative. At the very least one could get an inverted
reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must be
elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Post by john larkin
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I
found it was to look at the schematics. Look for module A22. Don't
think search works on such images, but visual search didn't take that
long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge,
near the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower
left region. Just above, look for INT and EXT jacks. The EXT jack is
where an external reference enters.
Joe Gwinn
It's just a block diagram of the reference oscillator module. There's no
detailed schematic of the oscillator itself. At least that's the case
with the PDF version of the Service Manual I have.
It's probably in the book that I don't have, if it was ever released.
Joe Gwinn
HP actually published at least 5 manuals of various kinds about this
analyzer, so it's possible it's in one of the others. However, the actual
service manual is where I'd expect to find it if they published it at all.
HP 8566B Operator's Manual
HP 8566B Installation and Verification Manual
HP 8566B Test and Adjustments Manual
HP 8566B Troubleshooting and Repair Manual
So if the answers are not in *any* of the above, it'd be jolly rotten luck
indeed!
Looking at that waveform again...
Could it be that the wavform you are seeing there is not a harmonic
but just a partial cancelation due to reflections ?
If you look at one peak vs. the other, they look about the same time
to me. About 1 scope division. Just the amplitude looks different on
alternating cycles. A non-linearity I would think would make an even
harmonic.
I thought I said the wrong thing ! I mean odd harmonic(s) from a
non-linearity.
Post by boB
2nd harmonic is usually due to non 1/2 wave symetry (DC
offset bascially)
Here, I meant even harmonic(s) not just second harmonic.

It's rather hot today in Phoenix..
Post by boB
What was tha amplitude after you loaded it down properly ? How about
a picture ?
Where were you scoping this at again ?
boB
Cursitor Doom
2024-06-01 12:07:45 UTC
Permalink
Post by boB
Post by boB
On Fri, 31 May 2024 21:40:04 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by Joe Gwinn
On Fri, 31 May 2024 18:54:06 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 18:53:29 -0400, Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 16:06:47 -0400, Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer,
I've found the 10Mhz reference oscillator is generating
an 'unsatisfactory waveform'
which may be causing the device to be unable to lock
it's main PLL. I've come across this waveshape before,
but mostly with oscillators I was building and in the
process of trying to iron out the wrinkles of and
certainly NOT a critical reference oscillator from a
respected manufacturer. Can anyone tell what's most
likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm
termination.
Arie
If the drive is a sine wave, a cable can't generate that
2nd harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of
those inexplicable mysteries that no one knows the answer
to. :)
That?s pretty diagnostic. There must be an LC filter on the
output?mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with
a resistor somewhere, the impedance presented to the feed
coax may be 50 ohms for positive input voltage, and say 10
Kohm for negative. At the very least one could get an
inverted reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must
be elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by Joe Gwinn
Post by Joe Gwinn
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I
found it was to look at the schematics. Look for module A22.
Don't think search works on such images, but visual search didn't
take that long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge,
near the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower
left region. Just above, look for INT and EXT jacks. The EXT jack
is where an external reference enters.
Joe Gwinn
It's just a block diagram of the reference oscillator module. There's
no detailed schematic of the oscillator itself. At least that's the
case with the PDF version of the Service Manual I have.
It's probably in the book that I don't have, if it was ever released.
Joe Gwinn
HP actually published at least 5 manuals of various kinds about this
analyzer, so it's possible it's in one of the others. However, the
actual service manual is where I'd expect to find it if they published
it at all.
HP 8566B Operator's Manual HP 8566B Installation and Verification
Manual HP 8566B Test and Adjustments Manual HP 8566B Troubleshooting
and Repair Manual
So if the answers are not in *any* of the above, it'd be jolly rotten
luck indeed!
Looking at that waveform again...
Could it be that the wavform you are seeing there is not a harmonic but
just a partial cancelation due to reflections ?
If you look at one peak vs. the other, they look about the same time to
me. About 1 scope division. Just the amplitude looks different on
alternating cycles. A non-linearity I would think would make an even
harmonic.
I thought I said the wrong thing ! I mean odd harmonic(s) from a
non-linearity.
Post by boB
2nd harmonic is usually due to non 1/2 wave symetry (DC
offset bascially)
Here, I meant even harmonic(s) not just second harmonic.
It's rather hot today in Phoenix..
1. Everybody makes careless mistakes.
2. I don't need high temperatures to make them!

I've taken a shot of the waveform into the 50 ohm input. It's around 850mV
peak-peak. Hopefully the slight distortion I spoke about is visible; the
slightly more leisurely negative-going excursions WRT their positive-going
counterparts. So it's not a pure sine wave as one would expect. Does it
matter? I don't know!

https://disk.yandex.com/i/7cuuBimDbOIBZw
Jeroen Belleman
2024-06-01 13:44:17 UTC
Permalink
Post by Cursitor Doom
Post by boB
Post by boB
On Fri, 31 May 2024 21:40:04 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by Joe Gwinn
On Fri, 31 May 2024 18:54:06 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 18:53:29 -0400, Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 16:06:47 -0400, Joe Gwinn
Post by Joe Gwinn
On Thu, 30 May 2024 15:02:44 -0400, Phil Hobbs
Post by Phil Hobbs
Post by Joe Gwinn
On Wed, 29 May 2024 22:11:47 -0000 (UTC), Phil Hobbs
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer,
I've found the 10Mhz reference oscillator is generating
an 'unsatisfactory waveform'
which may be causing the device to be unable to lock
it's main PLL. I've come across this waveshape before,
but mostly with oscillators I was building and in the
process of trying to iron out the wrinkles of and
certainly NOT a critical reference oscillator from a
respected manufacturer. Can anyone tell what's most
likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm
termination.
Arie
If the drive is a sine wave, a cable can't generate that
2nd harmonic.
I don't understand how a reflection can account for it either.
THe cable's only 4' long! However, with the 50 ohm input
enabled, the 2nd harmonic disappears. It's just one of
those inexplicable mysteries that no one knows the answer
to. :)
That?s pretty diagnostic. There must be an LC filter on the
output?mis-terminating it will cause all sorts of
frequency-response whoopdedoos.
It also occurs to me that if there is a diode in series with
a resistor somewhere, the impedance presented to the feed
coax may be 50 ohms for positive input voltage, and say 10
Kohm for negative. At the very least one could get an
inverted reflection on negative.
Joe Gwinn
Yeah, or an emitter follower. Good point.
Plus some LC filter wiggles, to distort and smooth things.
I dug around and found a copy of the HP 8566B spectrum analyzer
service manual. The 10 MHz ref input is an amplifier driving a mixer,
with not hint of for instance a TTL input. So, the problem must
be elsewhere. Or, it's just busted.
.<chrome-extension://efaidnbmnnnibpcajpcglclefindmkaj/https://
xdevs.com/doc/HP_Agilent_Keysight/
HP%208566B%20Troubleshooting%20&%20Repair%20Vol.%201.pdf>
Post by Joe Gwinn
Post by Joe Gwinn
Post by Joe Gwinn
Joe Gwinn
334 pages! Where is the issue?
The pagination was unclear, so I didn't see a way to say. How I
found it was to look at the schematics. Look for module A22.
Don't think search works on such images, but visual search didn't
take that long.
Joe Gwinn
Too much work for free consulting.
I took another look. There is a page reference on the right edge,
near the bottom, which is not marked as a page X of Y, but is.
Anyway, look at pages 59 and 77. At 77, look for A22 in the lower
left region. Just above, look for INT and EXT jacks. The EXT jack
is where an external reference enters.
Joe Gwinn
It's just a block diagram of the reference oscillator module. There's
no detailed schematic of the oscillator itself. At least that's the
case with the PDF version of the Service Manual I have.
It's probably in the book that I don't have, if it was ever released.
Joe Gwinn
HP actually published at least 5 manuals of various kinds about this
analyzer, so it's possible it's in one of the others. However, the
actual service manual is where I'd expect to find it if they published
it at all.
HP 8566B Operator's Manual HP 8566B Installation and Verification
Manual HP 8566B Test and Adjustments Manual HP 8566B Troubleshooting
and Repair Manual
So if the answers are not in *any* of the above, it'd be jolly rotten
luck indeed!
Looking at that waveform again...
Could it be that the wavform you are seeing there is not a harmonic but
just a partial cancelation due to reflections ?
If you look at one peak vs. the other, they look about the same time to
me. About 1 scope division. Just the amplitude looks different on
alternating cycles. A non-linearity I would think would make an even
harmonic.
I thought I said the wrong thing ! I mean odd harmonic(s) from a
non-linearity.
Post by boB
2nd harmonic is usually due to non 1/2 wave symetry (DC
offset bascially)
Here, I meant even harmonic(s) not just second harmonic.
It's rather hot today in Phoenix..
1. Everybody makes careless mistakes.
2. I don't need high temperatures to make them!
I've taken a shot of the waveform into the 50 ohm input. It's around 850mV
peak-peak. Hopefully the slight distortion I spoke about is visible; the
slightly more leisurely negative-going excursions WRT their positive-going
counterparts. So it's not a pure sine wave as one would expect. Does it
matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.

Jeroen Belleman
Cursitor Doom
2024-06-01 16:34:16 UTC
Permalink
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's around
850mV peak-peak. Hopefully the slight distortion I spoke about is
visible; the slightly more leisurely negative-going excursions WRT
their positive-going counterparts. So it's not a pure sine wave as one
would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
but here's my method:
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.

I shall consult the manual to see what it ought to be - if I can find it,
that is, as PDF manuals are a nightmare to navigate IME.
piglet
2024-06-01 22:00:58 UTC
Permalink
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's around
850mV peak-peak. Hopefully the slight distortion I spoke about is
visible; the slightly more leisurely negative-going excursions WRT
their positive-going counterparts. So it's not a pure sine wave as one
would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find it,
that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
--
piglet
piglet
2024-06-01 22:24:37 UTC
Permalink
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's around
850mV peak-peak. Hopefully the slight distortion I spoke about is
visible; the slightly more leisurely negative-going excursions WRT
their positive-going counterparts. So it's not a pure sine wave as one
would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find it,
that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Or +2.9dBm if using the 0.88v pk-pk I think is shown in the scope pic
rather than the 0.85v figure of your message.
--
piglet
Jeroen Belleman
2024-06-02 11:49:16 UTC
Permalink
Post by piglet
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's around
850mV peak-peak. Hopefully the slight distortion I spoke about is
visible; the slightly more leisurely negative-going excursions WRT
their positive-going counterparts. So it's not a pure sine wave as one
would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find it,
that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Or +2.9dBm if using the 0.88v pk-pk I think is shown in the scope pic
rather than the 0.85v figure of your message.
To CD:

The above is what I did. 30 + 10*log( (0.88/(2*sqrt(2)))^2 / 50) =
2.869 dBm. Rounded to 3dBm.

What's the issue with RMS vs. average?
Cursitor Doom
2024-06-02 12:09:48 UTC
Permalink
Post by Jeroen Belleman
Post by piglet
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find
it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Or +2.9dBm if using the 0.88v pk-pk I think is shown in the scope pic
rather than the 0.85v figure of your message.
The above is what I did. 30 + 10*log( (0.88/(2*sqrt(2)))^2 / 50) =
2.869 dBm. Rounded to 3dBm.
OK, thanks for that clarification. Anyway, I finally measured the power of
that oscillator with my HP RF power meter and it comes out at 1.74mW (or
about +2.5dBm off the top of my head). Seems a tad on the low side, but I
can't find what it's supposed to be in the manual.
Post by Jeroen Belleman
What's the issue with RMS vs. average?
When you dig into it, you find that what people really mean when they talk
about "RMS Watts" is actually *average* power. I found this on the web
which attempts to explain it:

https://agcsystems.tv/rms-power-fallacy/
Phil Hobbs
2024-06-02 12:59:30 UTC
Permalink
Post by Cursitor Doom
Post by Jeroen Belleman
Post by piglet
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find
it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Or +2.9dBm if using the 0.88v pk-pk I think is shown in the scope pic
rather than the 0.85v figure of your message.
The above is what I did. 30 + 10*log( (0.88/(2*sqrt(2)))^2 / 50) =
2.869 dBm. Rounded to 3dBm.
OK, thanks for that clarification. Anyway, I finally measured the power of
that oscillator with my HP RF power meter and it comes out at 1.74mW (or
about +2.5dBm off the top of my head). Seems a tad on the low side, but I
can't find what it's supposed to be in the manual.
Post by Jeroen Belleman
What's the issue with RMS vs. average?
When you dig into it, you find that what people really mean when they talk
about "RMS Watts" is actually *average* power. I found this on the web
https://agcsystems.tv/rms-power-fallacy/
It’s really not this hard.

“RMS” stands for “root mean square”, which is a shorthand description of
how you calculate the power delivered by an arbitrary voltage waveform (or
equivalently current) in a resistive circuit.

You square the instantaneous voltage, compute the mean (I. e. time
average), and then take the square root.

All those fudge factors like 0.5, 0.636, 0.707, and so forth, can be useful
for quick calculations, but they just summarize the results of the above
procedure _for_specific_situations_. Without first doing the math, and
understanding the situation, they’re worse than useless.

The ‘rms power’ thing came as a response to lying advertisements for stereo
systems, starting in the 1970s iirc. Crappy stereos were advertised as
producing “250 watts PMP”, for “peak music power”, as though that were a
thing. That led to very optimistic numbers, even before actual lies were
added, which they usually were.

People started pushing back by insisting on knowing what sine wave power
the amp could put out continuously without distorting or overheating.

That’s a very conservative spec, since music waveforms have a high peak/rms
ratio and the ear is most sensitive to transient distortion on the peaks.
It does have some basis in reality, though, and is easy to measure
unambiguously, which cuts through the Audio BS” (tm).

While saying “rms watts“ is indeed redundant, strictly speaking,
nevertheless it’s a useful shorthand for describing audio amps, Chinese
switchers, and (I suppose) power FETs.

Cheers

Phil Hobbs
--
Dr Philip C D Hobbs Principal Consultant ElectroOptical Innovations LLC /
Hobbs ElectroOptics Optics, Electro-optics, Photonics, Analog Electronics
Cursitor Doom
2024-06-02 13:53:55 UTC
Permalink
Post by Phil Hobbs
Post by Cursitor Doom
Post by Jeroen Belleman
Post by piglet
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators
most often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can
find it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Or +2.9dBm if using the 0.88v pk-pk I think is shown in the scope pic
rather than the 0.85v figure of your message.
The above is what I did. 30 + 10*log( (0.88/(2*sqrt(2)))^2 / 50) =
2.869 dBm. Rounded to 3dBm.
OK, thanks for that clarification. Anyway, I finally measured the power
of that oscillator with my HP RF power meter and it comes out at 1.74mW
(or about +2.5dBm off the top of my head). Seems a tad on the low side,
but I can't find what it's supposed to be in the manual.
Post by Jeroen Belleman
What's the issue with RMS vs. average?
When you dig into it, you find that what people really mean when they
talk about "RMS Watts" is actually *average* power. I found this on the
https://agcsystems.tv/rms-power-fallacy/
It’s really not this hard.
“RMS” stands for “root mean square”, which is a shorthand description of
how you calculate the power delivered by an arbitrary voltage waveform
(or equivalently current) in a resistive circuit.
You square the instantaneous voltage, compute the mean (I. e. time
average), and then take the square root.
All those fudge factors like 0.5, 0.636, 0.707, and so forth, can be
useful for quick calculations, but they just summarize the results of
the above procedure _for_specific_situations_. Without first doing the
math, and understanding the situation, they’re worse than useless.
The ‘rms power’ thing came as a response to lying advertisements for
stereo systems, starting in the 1970s iirc. Crappy stereos were
advertised as producing “250 watts PMP”, for “peak music power”, as
though that were a thing. That led to very optimistic numbers, even
before actual lies were added, which they usually were.
People started pushing back by insisting on knowing what sine wave power
the amp could put out continuously without distorting or overheating.
That’s a very conservative spec, since music waveforms have a high
peak/rms ratio and the ear is most sensitive to transient distortion on
the peaks.
It does have some basis in reality, though, and is easy to measure
unambiguously, which cuts through the Audio BS” (tm).
While saying “rms watts“ is indeed redundant, strictly speaking,
nevertheless it’s a useful shorthand for describing audio amps, Chinese
switchers, and (I suppose) power FETs.
Cheers
Phil Hobbs
Phil, I believe you also have an 8566B. Do you know what the 10Mhz
reference oscillator output level should be? Is yours anything close to
+2.5dBm?
Jeroen Belleman
2024-06-02 18:05:43 UTC
Permalink
Post by Cursitor Doom
Post by Jeroen Belleman
Post by piglet
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find
it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Or +2.9dBm if using the 0.88v pk-pk I think is shown in the scope pic
rather than the 0.85v figure of your message.
The above is what I did. 30 + 10*log( (0.88/(2*sqrt(2)))^2 / 50) =
2.869 dBm. Rounded to 3dBm.
OK, thanks for that clarification. Anyway, I finally measured the power of
that oscillator with my HP RF power meter and it comes out at 1.74mW (or
about +2.5dBm off the top of my head). Seems a tad on the low side, but I
can't find what it's supposed to be in the manual.
Post by Jeroen Belleman
What's the issue with RMS vs. average?
When you dig into it, you find that what people really mean when they talk
about "RMS Watts" is actually *average* power. I found this on the web
https://agcsystems.tv/rms-power-fallacy/
Average power is not the same as average voltage! Average power is
proportional to the average of the voltage squared. It makes a
difference!

Jeroen Belleman
Cursitor Doom
2024-06-02 19:37:26 UTC
Permalink
Post by Jeroen Belleman
Post by Cursitor Doom
Post by Jeroen Belleman
Post by piglet
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators
most often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can
find it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Or +2.9dBm if using the 0.88v pk-pk I think is shown in the scope pic
rather than the 0.85v figure of your message.
The above is what I did. 30 + 10*log( (0.88/(2*sqrt(2)))^2 / 50) =
2.869 dBm. Rounded to 3dBm.
OK, thanks for that clarification. Anyway, I finally measured the power
of that oscillator with my HP RF power meter and it comes out at 1.74mW
(or about +2.5dBm off the top of my head). Seems a tad on the low side,
but I can't find what it's supposed to be in the manual.
Post by Jeroen Belleman
What's the issue with RMS vs. average?
When you dig into it, you find that what people really mean when they
talk about "RMS Watts" is actually *average* power. I found this on the
https://agcsystems.tv/rms-power-fallacy/
Average power is not the same as average voltage! Average power is
proportional to the average of the voltage squared. It makes a
difference!
Jeroen Belleman
Sorry, but I don't recall anyone claiming average power and average
voltage were the same thing!
Jeroen Belleman
2024-06-02 21:31:38 UTC
Permalink
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
Post by Jeroen Belleman
Post by piglet
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators
most often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can
find it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Or +2.9dBm if using the 0.88v pk-pk I think is shown in the scope pic
rather than the 0.85v figure of your message.
The above is what I did. 30 + 10*log( (0.88/(2*sqrt(2)))^2 / 50) =
2.869 dBm. Rounded to 3dBm.
OK, thanks for that clarification. Anyway, I finally measured the power
of that oscillator with my HP RF power meter and it comes out at 1.74mW
(or about +2.5dBm off the top of my head). Seems a tad on the low side,
but I can't find what it's supposed to be in the manual.
Post by Jeroen Belleman
What's the issue with RMS vs. average?
When you dig into it, you find that what people really mean when they
talk about "RMS Watts" is actually *average* power. I found this on the
https://agcsystems.tv/rms-power-fallacy/
Average power is not the same as average voltage! Average power is
proportional to the average of the voltage squared. It makes a
difference!
Jeroen Belleman
Sorry, but I don't recall anyone claiming average power and average
voltage were the same thing!
Earlier, you said, I cite, "Average power is average volts squared
divided by the load impedance".

It isn't. It's RMS volts squared divided by load impedance.

Jeroen Belleman
Cursitor Doom
2024-06-02 21:59:22 UTC
Permalink
Post by Jeroen Belleman
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
Post by Jeroen Belleman
Post by piglet
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators
most often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can
find it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Or +2.9dBm if using the 0.88v pk-pk I think is shown in the scope
pic rather than the 0.85v figure of your message.
The above is what I did. 30 + 10*log( (0.88/(2*sqrt(2)))^2 / 50) =
2.869 dBm. Rounded to 3dBm.
OK, thanks for that clarification. Anyway, I finally measured the
power of that oscillator with my HP RF power meter and it comes out
at 1.74mW (or about +2.5dBm off the top of my head). Seems a tad on
the low side,
but I can't find what it's supposed to be in the manual.
Post by Jeroen Belleman
What's the issue with RMS vs. average?
When you dig into it, you find that what people really mean when they
talk about "RMS Watts" is actually *average* power. I found this on
https://agcsystems.tv/rms-power-fallacy/
Average power is not the same as average voltage! Average power is
proportional to the average of the voltage squared. It makes a
difference!
Jeroen Belleman
Sorry, but I don't recall anyone claiming average power and average
voltage were the same thing!
Earlier, you said, I cite, "Average power is average volts squared
divided by the load impedance".
It isn't. It's RMS volts squared divided by load impedance.
Jeroen Belleman
Thanks for that clarification.
Cursitor Doom
2024-06-02 10:32:58 UTC
Permalink
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's around
850mV peak-peak. Hopefully the slight distortion I spoke about is
visible; the slightly more leisurely negative-going excursions WRT
their positive-going counterparts. So it's not a pure sine wave as
one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is
0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find
it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly speaking
IIRC, so that's why I took the average figure; not that it makes much
difference in practice. it does seem a bit on the low side, but despite
reading through the most likely sources (the service manual and the
trouble-shooting/repair manual) I can find nothing stated for what that
signal level should be! This may be due to the user-unfriendliness of very
large PDF manuals; I just don't know. Anyway, not very satisfactory! Later
today I plan to do a direct power meter measurement of the ref osc (since
none of us here seem to agree on what 850mV vs 50 ohms equates to!!)
piglet
2024-06-02 11:17:58 UTC
Permalink
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's around
850mV peak-peak. Hopefully the slight distortion I spoke about is
visible; the slightly more leisurely negative-going excursions WRT
their positive-going counterparts. So it's not a pure sine wave as
one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is
0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find
it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly speaking
IIRC, so that's why I took the average figure; not that it makes much
difference in practice. it does seem a bit on the low side, but despite
reading through the most likely sources (the service manual and the
trouble-shooting/repair manual) I can find nothing stated for what that
signal level should be! This may be due to the user-unfriendliness of very
large PDF manuals; I just don't know. Anyway, not very satisfactory! Later
today I plan to do a direct power meter measurement of the ref osc (since
none of us here seem to agree on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope why not
measure the peak to peak voltage on the scope and power on the power meter
and see which calculation 0.636 vs 0.707 gives the closest agreement?
--
piglet
Cursitor Doom
2024-06-02 11:31:33 UTC
Permalink
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find
it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that it
makes much difference in practice. it does seem a bit on the low side,
but despite reading through the most likely sources (the service manual
and the trouble-shooting/repair manual) I can find nothing stated for
what that signal level should be! This may be due to the
user-unfriendliness of very large PDF manuals; I just don't know.
Anyway, not very satisfactory! Later today I plan to do a direct power
meter measurement of the ref osc (since none of us here seem to agree
on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope why
not measure the peak to peak voltage on the scope and power on the power
meter and see which calculation 0.636 vs 0.707 gives the closest
agreement?
It wouldn't prove anything one way or ther other, though, since that power
meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be accurate
enough to meaningfully test your otherwise fine suggestion.
John R Walliker
2024-06-02 12:00:21 UTC
Permalink
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find
it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that it
makes much difference in practice. it does seem a bit on the low side,
but despite reading through the most likely sources (the service manual
and the trouble-shooting/repair manual) I can find nothing stated for
what that signal level should be! This may be due to the
user-unfriendliness of very large PDF manuals; I just don't know.
Anyway, not very satisfactory! Later today I plan to do a direct power
meter measurement of the ref osc (since none of us here seem to agree
on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope why
not measure the peak to peak voltage on the scope and power on the power
meter and see which calculation 0.636 vs 0.707 gives the closest
agreement?
It wouldn't prove anything one way or ther other, though, since that power
meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be accurate
enough to meaningfully test your otherwise fine suggestion.
I have an 8566B which is currently not working. Both the status leds
on the front panel at the bottom are red. I haven't started to
investigate yet.
The fault developed slowly. At first it would sometimes work, then
progressively less often and now never.
However, if the signal being discussed is available on the rear panel
I could measure mine and see what it looks like and what voltage
is delivered.
John
Cursitor Doom
2024-06-02 12:12:53 UTC
Permalink
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators
most often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can
find it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that it
makes much difference in practice. it does seem a bit on the low
side, but despite reading through the most likely sources (the
service manual and the trouble-shooting/repair manual) I can find
nothing stated for what that signal level should be! This may be due
to the user-unfriendliness of very large PDF manuals; I just don't
know. Anyway, not very satisfactory! Later today I plan to do a
direct power meter measurement of the ref osc (since none of us here
seem to agree on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope why
not measure the peak to peak voltage on the scope and power on the
power meter and see which calculation 0.636 vs 0.707 gives the closest
agreement?
It wouldn't prove anything one way or ther other, though, since that
power meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be
accurate enough to meaningfully test your otherwise fine suggestion.
I have an 8566B which is currently not working. Both the status leds on
the front panel at the bottom are red. I haven't started to investigate
yet.
The fault developed slowly. At first it would sometimes work, then
progressively less often and now never.
However, if the signal being discussed is available on the rear panel I
could measure mine and see what it looks like and what voltage is
delivered.
John
Yes, that could be very helpful, John, since your fault is clearly totally
different to mine. Peak to peak volts into 50 ohms on a scope will be fine
if don't have access to an RF power meter.
Jan Panteltje
2024-06-02 12:34:29 UTC
Permalink
On a sunny day (Sun, 2 Jun 2024 12:12:53 -0000 (UTC)) it happened Cursitor
Post by Cursitor Doom
Peak to peak volts into 50 ohms on a scope will be fine
if don't have access to an RF power meter.
No idea what you are up to,
but effective power can me measured this way:
signal into dummy load, measure temperature rise of dummy load.
Now try same with DC on dummy load, measure temperature rise
set DC voltage to same temperature rise.
Ohm's law gives you Watts,
Loading Image...
Or build you own power meter
Cursitor Doom
2024-06-02 13:51:31 UTC
Permalink
Post by Jan Panteltje
On a sunny day (Sun, 2 Jun 2024 12:12:53 -0000 (UTC)) it happened
Peak to peak volts into 50 ohms on a scope will be fine if don't have
access to an RF power meter.
No idea what you are up to,
signal into dummy load, measure temperature rise of dummy load.
Now try same with DC on dummy load, measure temperature rise set DC
voltage to same temperature rise.
My old HP RF power meter uses this principle. It has a thermistor sensor
head which is remarkably sensitive down into the microwatt range. Not only
that, but there isn't any noticeable thermal lag, even at very low power
levels, so the meter needle instantly flicks over to give the power
reading. I've often wondered how they do that. More modern meters use a
different principle IIRC.
Post by Jan Panteltje
Ohm's law gives you Watts,
https://panteltje.nl/pub/250W_1_GHz_dummy_load_IMG_4563.JPG
Or build you own power meter
Building myown RF power meter to emulate what a commercial one can do is
way above my capabilities, sadly, Jan.
John R Walliker
2024-06-03 21:44:19 UTC
Permalink
Post by Cursitor Doom
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators
most often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can
find it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that it
makes much difference in practice. it does seem a bit on the low
side, but despite reading through the most likely sources (the
service manual and the trouble-shooting/repair manual) I can find
nothing stated for what that signal level should be! This may be due
to the user-unfriendliness of very large PDF manuals; I just don't
know. Anyway, not very satisfactory! Later today I plan to do a
direct power meter measurement of the ref osc (since none of us here
seem to agree on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope why
not measure the peak to peak voltage on the scope and power on the
power meter and see which calculation 0.636 vs 0.707 gives the closest
agreement?
It wouldn't prove anything one way or ther other, though, since that
power meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be
accurate enough to meaningfully test your otherwise fine suggestion.
I have an 8566B which is currently not working. Both the status leds on
the front panel at the bottom are red. I haven't started to investigate
yet.
The fault developed slowly. At first it would sometimes work, then
progressively less often and now never.
However, if the signal being discussed is available on the rear panel I
could measure mine and see what it looks like and what voltage is
delivered.
John
Yes, that could be very helpful, John, since your fault is clearly totally
different to mine. Peak to peak volts into 50 ohms on a scope will be fine
if don't have access to an RF power meter.
I measured the 10MHz output of my unit with an HP 54542A digital storage
'scope and found the following:
1Mohm input via 5m coax
1.133 Vp-p
405.8 mVrms

50ohm input via 5m coax
790.3 mVp-p
284.9 mVrms

The waveform with 1Mohm load looked like a perfect sine wave, whereas
the 50 ohm loaded waveform showed some second harmonic distortion
visible as a slight narrowing of the top of the sine and a slight
flattening of the bottom of the sine.

The frequency measured with an HP 53131A frequency counter
was 10.000199MHz.
The spectrum analyzer had been on standby for a few weeks and fully
powered for a few hours, so the crystal oven should have been
at equilibrium. I then substituted my rubidium oscillator which
indicated 9.999997MHz on the counter.

The connector that I used was the one labelled 10MHz at bottom right,
not the adjacent reference output which is connected to a reference
input with a short coax jumper. Is the same output that you measured?

John
Cursitor Doom
2024-06-05 17:09:31 UTC
Permalink
Post by John R Walliker
Post by Cursitor Doom
Post by John R Walliker
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators
most often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can
find it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that it
makes much difference in practice. it does seem a bit on the low
side, but despite reading through the most likely sources (the
service manual and the trouble-shooting/repair manual) I can find
nothing stated for what that signal level should be! This may be
due to the user-unfriendliness of very large PDF manuals; I just
don't know. Anyway, not very satisfactory! Later today I plan to do
a direct power meter measurement of the ref osc (since none of us
here seem to agree on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope
why not measure the peak to peak voltage on the scope and power on
the power meter and see which calculation 0.636 vs 0.707 gives the
closest agreement?
It wouldn't prove anything one way or ther other, though, since that
power meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be
accurate enough to meaningfully test your otherwise fine suggestion.
I have an 8566B which is currently not working. Both the status leds
on the front panel at the bottom are red. I haven't started to
investigate yet.
The fault developed slowly. At first it would sometimes work, then
progressively less often and now never.
However, if the signal being discussed is available on the rear panel
I could measure mine and see what it looks like and what voltage is
delivered.
John
Yes, that could be very helpful, John, since your fault is clearly
totally different to mine. Peak to peak volts into 50 ohms on a scope
will be fine if don't have access to an RF power meter.
I measured the 10MHz output of my unit with an HP 54542A digital storage
1Mohm input via 5m coax 1.133 Vp-p 405.8 mVrms
50ohm input via 5m coax 790.3 mVp-p 284.9 mVrms
The waveform with 1Mohm load looked like a perfect sine wave, whereas
the 50 ohm loaded waveform showed some second harmonic distortion
visible as a slight narrowing of the top of the sine and a slight
flattening of the bottom of the sine.
The frequency measured with an HP 53131A frequency counter was
10.000199MHz.
The spectrum analyzer had been on standby for a few weeks and fully
powered for a few hours, so the crystal oven should have been at
equilibrium. I then substituted my rubidium oscillator which indicated
9.999997MHz on the counter.
The connector that I used was the one labelled 10MHz at bottom right,
not the adjacent reference output which is connected to a reference
input with a short coax jumper. Is the same output that you measured?
John
Hi John, sorry for the delay in replying.
You got some interesting results there. Not what I'd expected, to be
honest. We have to bear in mind that the 8566B is a different beast to
yours, of course, so a bit of leeway can be allowed for that.
Nevertheless, the fact you're getting a decent sine wave into 1Meg is
curious, given what I experienced. I'm taking my 10Mhz from a BNC socket
on the rear panel which HP placed there to make it easier to check and
adjust the 10.0000000Mhz out as precisely as possible. I'm sure yours
*will* be different, but that shouldn't matter. I also got the same
results by popping off one of the 50 ohm interconnects from the board the
A22 10Mhz ref feeds into.
Thanks for including the p-p voltage figures in your report; helps a lot.
Many thanks again.

Joe Gwinn
2024-06-02 16:19:05 UTC
Permalink
On Sun, 2 Jun 2024 11:31:33 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find
it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that it
makes much difference in practice. it does seem a bit on the low side,
but despite reading through the most likely sources (the service manual
and the trouble-shooting/repair manual) I can find nothing stated for
what that signal level should be! This may be due to the
user-unfriendliness of very large PDF manuals; I just don't know.
Anyway, not very satisfactory! Later today I plan to do a direct power
meter measurement of the ref osc (since none of us here seem to agree
on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope why
not measure the peak to peak voltage on the scope and power on the power
meter and see which calculation 0.636 vs 0.707 gives the closest
agreement?
It wouldn't prove anything one way or ther other, though, since that power
meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be accurate
enough to meaningfully test your otherwise fine suggestion.
The 0 to +10 dBm range I mentioned came from the service manual.

Looking at your scope picture, it looks like a 3 Vpp signal, which is
+13 dBm, a very common distribution level, but one that exceeds the
analyzer's allowed range. All that's needed to fix this is a 3dB
inline attenuator. Here is one for SMA connectors:

.<https://www.amazon.com/MWRF-Source-Male-Female-Attenuator/dp/B07MP9D9GC?th=1>

Just buying a few of these and doing some experiments will be far
cheaper and faster than the various alternatives discussed.

Joe Gwinn
Cursitor Doom
2024-06-02 16:55:28 UTC
Permalink
Post by Joe Gwinn
On Sun, 2 Jun 2024 11:31:33 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators
most often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can
find it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that it
makes much difference in practice. it does seem a bit on the low
side, but despite reading through the most likely sources (the
service manual and the trouble-shooting/repair manual) I can find
nothing stated for what that signal level should be! This may be due
to the user-unfriendliness of very large PDF manuals; I just don't
know. Anyway, not very satisfactory! Later today I plan to do a
direct power meter measurement of the ref osc (since none of us here
seem to agree on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope why
not measure the peak to peak voltage on the scope and power on the
power meter and see which calculation 0.636 vs 0.707 gives the closest
agreement?
It wouldn't prove anything one way or ther other, though, since that
power meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be
accurate enough to meaningfully test your otherwise fine suggestion.
The 0 to +10 dBm range I mentioned came from the service manual.
Looking at your scope picture, it looks like a 3 Vpp signal, which is
+13 dBm, a very common distribution level, but one that exceeds the
analyzer's allowed range. All that's needed to fix this is a 3dB inline
.<https://www.amazon.com/MWRF-Source-Male-Female-Attenuator/dp/
B07MP9D9GC?th=1>
Post by Joe Gwinn
Just buying a few of these and doing some experiments will be far
cheaper and faster than the various alternatives discussed.t
Joe Gwinn
I think you're looking at the first picture with the signal into the
scope's 1 Meg input. The 50 ohm trace is only 850mV peak-to-peak or
thereabouts and when I measured it with an actual power meter, came out at
about +2.5dBm so within the range you stated; no attenuation needed
(thanks for the range, by the way; I needed to know that).

I've now measured the 100Mhz oscillator and that seems fine, although I
only saw 0.61V p-p into 50 ohms, so somewhat less than the 10Mhz
oscillator's output.
So far, I've not measured anything which screams "the fault's here!" as
all the expected signals are present - although admittedly I have many
more to test. But certainly all the *major* signals within this complex
beast are present. It's looking like it could be an issue with one of the
phase detectors or LPFs. Sigh....
Joe Gwinn
2024-06-02 18:08:48 UTC
Permalink
On Sun, 2 Jun 2024 16:55:28 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
On Sun, 2 Jun 2024 11:31:33 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators
most often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can
find it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that it
makes much difference in practice. it does seem a bit on the low
side, but despite reading through the most likely sources (the
service manual and the trouble-shooting/repair manual) I can find
nothing stated for what that signal level should be! This may be due
to the user-unfriendliness of very large PDF manuals; I just don't
know. Anyway, not very satisfactory! Later today I plan to do a
direct power meter measurement of the ref osc (since none of us here
seem to agree on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope why
not measure the peak to peak voltage on the scope and power on the
power meter and see which calculation 0.636 vs 0.707 gives the closest
agreement?
It wouldn't prove anything one way or ther other, though, since that
power meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be
accurate enough to meaningfully test your otherwise fine suggestion.
The 0 to +10 dBm range I mentioned came from the service manual.
Looking at your scope picture, it looks like a 3 Vpp signal, which is
+13 dBm, a very common distribution level, but one that exceeds the
analyzer's allowed range. All that's needed to fix this is a 3dB inline
.<https://www.amazon.com/MWRF-Source-Male-Female-Attenuator/dp/
B07MP9D9GC?th=1>
Post by Joe Gwinn
Just buying a few of these and doing some experiments will be far
cheaper and faster than the various alternatives discussed.t
Joe Gwinn
I think you're looking at the first picture with the signal into the
scope's 1 Meg input. The 50 ohm trace is only 850mV peak-to-peak or
thereabouts and when I measured it with an actual power meter, came out at
about +2.5dBm so within the range you stated; no attenuation needed
(thanks for the range, by the way; I needed to know that).
What we don't know is exactly how you made the various measurements.
If you are observing the signal from the 10 MHz reference where it
enters the analyzer, I would expect that there is a T-connector with
the scope (set to 1 Mohm) listening in to passing signals.

In this case, the load seen by the incoming reference is that provided
by the input on the analyzer. Which input is +10 dBm max. If you set
the observing scope input to 50 ohm, the reference will see a 25 ohm
load, cutting the signal seen by the analyzer by 3 dB. Which will
take +13 dBm down to +10 dBm, which is in range.

A 3dB attenuator in line will drop the signal to 10 dBm as well.

I've built lots of systems like that. The 10 MHz reference is
delivered to everybody at +13 dBm, and it is the receivers'
responsibility to attenuate it to whatever they need.
Post by Joe Gwinn
I've now measured the 100Mhz oscillator and that seems fine, although I
only saw 0.61V p-p into 50 ohms, so somewhat less than the 10Mhz
oscillator's output.
So far, I've not measured anything which screams "the fault's here!" as
all the expected signals are present - although admittedly I have many
more to test. But certainly all the *major* signals within this complex
beast are present. It's looking like it could be an issue with one of the
phase detectors or LPFs. Sigh....
To my eye, it does scream.

Joe Gwinn
Cursitor Doom
2024-06-02 20:58:45 UTC
Permalink
Post by Joe Gwinn
On Sun, 2 Jun 2024 16:55:28 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
On Sun, 2 Jun 2024 11:31:33 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators
most often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can
find it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that it
makes much difference in practice. it does seem a bit on the low
side, but despite reading through the most likely sources (the
service manual and the trouble-shooting/repair manual) I can find
nothing stated for what that signal level should be! This may be
due to the user-unfriendliness of very large PDF manuals; I just
don't know. Anyway, not very satisfactory! Later today I plan to do
a direct power meter measurement of the ref osc (since none of us
here seem to agree on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope
why not measure the peak to peak voltage on the scope and power on
the power meter and see which calculation 0.636 vs 0.707 gives the
closest agreement?
It wouldn't prove anything one way or ther other, though, since that
power meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be
accurate enough to meaningfully test your otherwise fine suggestion.
The 0 to +10 dBm range I mentioned came from the service manual.
Looking at your scope picture, it looks like a 3 Vpp signal, which is
+13 dBm, a very common distribution level, but one that exceeds the
analyzer's allowed range. All that's needed to fix this is a 3dB
.<https://www.amazon.com/MWRF-Source-Male-Female-Attenuator/dp/
B07MP9D9GC?th=1>
Post by Joe Gwinn
Just buying a few of these and doing some experiments will be far
cheaper and faster than the various alternatives discussed.t
Joe Gwinn
I think you're looking at the first picture with the signal into the
scope's 1 Meg input. The 50 ohm trace is only 850mV peak-to-peak or
thereabouts and when I measured it with an actual power meter, came out
at about +2.5dBm so within the range you stated; no attenuation needed
(thanks for the range, by the way; I needed to know that).
What we don't know is exactly how you made the various measurements. If
you are observing the signal from the 10 MHz reference where it enters
the analyzer, I would expect that there is a T-connector with the scope
(set to 1 Mohm) listening in to passing signals.
You did ask me this before and did post an answer. See Message-ID:
<v3fsbp$2u0a6$***@dont-email.me>

You also still appear to think that the 10Mhz signal is going into the
Post by Joe Gwinn
In this case, the load seen by the incoming reference is that provided
by the input on the analyzer. Which input is +10 dBm max. If you set
the observing scope input to 50 ohm, the reference will see a 25 ohm
load, cutting the signal seen by the analyzer by 3 dB. Which will take
+13 dBm down to +10 dBm, which is in range.
A 3dB attenuator in line will drop the signal to 10 dBm as well.
I've built lots of systems like that. The 10 MHz reference is delivered
to everybody at +13 dBm, and it is the receivers' responsibility to
attenuate it to whatever they need.
Post by Joe Gwinn
I've now measured the 100Mhz oscillator and that seems fine, although I
only saw 0.61V p-p into 50 ohms, so somewhat less than the 10Mhz
oscillator's output.
So far, I've not measured anything which screams "the fault's here!" as
all the expected signals are present - although admittedly I have many
more to test. But certainly all the *major* signals within this complex
beast are present. It's looking like it could be an issue with one of
the phase detectors or LPFs. Sigh....
To my eye, it does scream.
Joe Gwinn
Joe Gwinn
2024-06-03 11:48:32 UTC
Permalink
On Sun, 2 Jun 2024 20:58:45 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by Joe Gwinn
On Sun, 2 Jun 2024 16:55:28 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
On Sun, 2 Jun 2024 11:31:33 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
<https://disk.yandex.com/i/7cuuBimDbOIBZw>
And <https://disk.yandex.com/i/z6fYbeVfPRK7aA>
Post by Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
Post by Joe Gwinn
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators
most often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can
find it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that it
makes much difference in practice. it does seem a bit on the low
side, but despite reading through the most likely sources (the
service manual and the trouble-shooting/repair manual) I can find
nothing stated for what that signal level should be! This may be
due to the user-unfriendliness of very large PDF manuals; I just
don't know. Anyway, not very satisfactory! Later today I plan to do
a direct power meter measurement of the ref osc (since none of us
here seem to agree on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope
why not measure the peak to peak voltage on the scope and power on
the power meter and see which calculation 0.636 vs 0.707 gives the
closest agreement?
It wouldn't prove anything one way or ther other, though, since that
power meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be
accurate enough to meaningfully test your otherwise fine suggestion.
The 0 to +10 dBm range I mentioned came from the service manual.
Looking at your scope picture, it looks like a 3 Vpp signal, which is
+13 dBm, a very common distribution level, but one that exceeds the
analyzer's allowed range. All that's needed to fix this is a 3dB
.<https://www.amazon.com/MWRF-Source-Male-Female-Attenuator/dp/
B07MP9D9GC?th=1>
Post by Joe Gwinn
Just buying a few of these and doing some experiments will be far
cheaper and faster than the various alternatives discussed.t
Joe Gwinn
I think you're looking at the first picture with the signal into the
scope's 1 Meg input. The 50 ohm trace is only 850mV peak-to-peak or
thereabouts and when I measured it with an actual power meter, came out
at about +2.5dBm so within the range you stated; no attenuation needed
(thanks for the range, by the way; I needed to know that).
What we don't know is exactly how you made the various measurements. If
you are observing the signal from the 10 MHz reference where it enters
the analyzer, I would expect that there is a T-connector with the scope
(set to 1 Mohm) listening in to passing signals.
You also still appear to think that the 10Mhz signal is going into the
I did read that, but didn't know what to make of it. I think an
annotated drawing is required.

On this drawing, where do the various scope traces mentioned up-thread
come from?

Joe Gwinn
Post by Cursitor Doom
Post by Joe Gwinn
In this case, the load seen by the incoming reference is that provided
by the input on the analyzer. Which input is +10 dBm max. If you set
the observing scope input to 50 ohm, the reference will see a 25 ohm
load, cutting the signal seen by the analyzer by 3 dB. Which will take
+13 dBm down to +10 dBm, which is in range.
A 3dB attenuator in line will drop the signal to 10 dBm as well.
I've built lots of systems like that. The 10 MHz reference is delivered
to everybody at +13 dBm, and it is the receivers' responsibility to
attenuate it to whatever they need.
Post by Joe Gwinn
I've now measured the 100Mhz oscillator and that seems fine, although I
only saw 0.61V p-p into 50 ohms, so somewhat less than the 10Mhz
oscillator's output.
So far, I've not measured anything which screams "the fault's here!" as
all the expected signals are present - although admittedly I have many
more to test. But certainly all the *major* signals within this complex
beast are present. It's looking like it could be an issue with one of
the phase detectors or LPFs. Sigh....
To my eye, it does scream.
Joe Gwinn
Cursitor Doom
2024-06-03 15:43:25 UTC
Permalink
Post by Joe Gwinn
On Sun, 2 Jun 2024 20:58:45 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by Joe Gwinn
On Sun, 2 Jun 2024 16:55:28 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
On Sun, 2 Jun 2024 11:31:33 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I
spoke about is visible; the slightly more leisurely
negative-going excursions WRT their positive-going
counterparts. So it's not a pure sine wave as one would
expect. Does it matter? I don't know!
<https://disk.yandex.com/i/7cuuBimDbOIBZw>
And <https://disk.yandex.com/i/z6fYbeVfPRK7aA>
Post by Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
Post by Joe Gwinn
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators
most often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be
corrected,
850mV peak to peak is 425mV peak voltage. Average of that is
0.425x0.636 =
0.27V. Average power is average volts squared divided by the
load impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I
can find it, that is, as PDF manuals are a nightmare to
navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that
it makes much difference in practice. it does seem a bit on the
low side, but despite reading through the most likely sources
(the service manual and the trouble-shooting/repair manual) I can
find nothing stated for what that signal level should be! This
may be due to the user-unfriendliness of very large PDF manuals;
I just don't know. Anyway, not very satisfactory! Later today I
plan to do a direct power meter measurement of the ref osc (since
none of us here seem to agree on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope
why not measure the peak to peak voltage on the scope and power on
the power meter and see which calculation 0.636 vs 0.707 gives the
closest agreement?
It wouldn't prove anything one way or ther other, though, since that
power meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be
accurate enough to meaningfully test your otherwise fine suggestion.
The 0 to +10 dBm range I mentioned came from the service manual.
Looking at your scope picture, it looks like a 3 Vpp signal, which
is +13 dBm, a very common distribution level, but one that exceeds
the analyzer's allowed range. All that's needed to fix this is a
.<https://www.amazon.com/MWRF-Source-Male-Female-Attenuator/dp/
B07MP9D9GC?th=1>
Post by Joe Gwinn
Just buying a few of these and doing some experiments will be far
cheaper and faster than the various alternatives discussed.t
Joe Gwinn
I think you're looking at the first picture with the signal into the
scope's 1 Meg input. The 50 ohm trace is only 850mV peak-to-peak or
thereabouts and when I measured it with an actual power meter, came
out at about +2.5dBm so within the range you stated; no attenuation
needed (thanks for the range, by the way; I needed to know that).
What we don't know is exactly how you made the various measurements.
If you are observing the signal from the 10 MHz reference where it
enters the analyzer, I would expect that there is a T-connector with
the scope (set to 1 Mohm) listening in to passing signals.
You also still appear to think that the 10Mhz signal is going into the
I did read that, but didn't know what to make of it. I think an
annotated drawing is required.
On this drawing, where do the various scope traces mentioned up-thread
come from?
Joe Gwinn
Post by Cursitor Doom
Post by Joe Gwinn
In this case, the load seen by the incoming reference is that provided
by the input on the analyzer. Which input is +10 dBm max. If you set
the observing scope input to 50 ohm, the reference will see a 25 ohm
load, cutting the signal seen by the analyzer by 3 dB. Which will
take +13 dBm down to +10 dBm, which is in range.
A 3dB attenuator in line will drop the signal to 10 dBm as well.
I've built lots of systems like that. The 10 MHz reference is
delivered to everybody at +13 dBm, and it is the receivers'
responsibility to attenuate it to whatever they need.
Post by Joe Gwinn
I've now measured the 100Mhz oscillator and that seems fine, although
I only saw 0.61V p-p into 50 ohms, so somewhat less than the 10Mhz
oscillator's output.
So far, I've not measured anything which screams "the fault's here!"
as all the expected signals are present - although admittedly I have
many more to test. But certainly all the *major* signals within this
complex beast are present. It's looking like it could be an issue with
one of the phase detectors or LPFs. Sigh....
To my eye, it does scream.
Joe Gwinn
Joe, I appreciate you're only trying to help, but don't worry about it. I
don't believe the oscillator this thread relates to is causing the PLL
unlock error so we've all gone down a bit of a rabbit hole with this one.
I really need to look elsewhere for the culprit.
Jeroen Belleman
2024-06-03 17:38:21 UTC
Permalink
Post by Cursitor Doom
Post by Joe Gwinn
On Sun, 2 Jun 2024 20:58:45 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by Joe Gwinn
On Sun, 2 Jun 2024 16:55:28 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
On Sun, 2 Jun 2024 11:31:33 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I
spoke about is visible; the slightly more leisurely
negative-going excursions WRT their positive-going
counterparts. So it's not a pure sine wave as one would
expect. Does it matter? I don't know!
<https://disk.yandex.com/i/7cuuBimDbOIBZw>
And <https://disk.yandex.com/i/z6fYbeVfPRK7aA>
Post by Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
Post by Joe Gwinn
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
The shape looks perfectly acceptable to me. This is +3dBm into
50 Ohms.
Is that what it's supposed to be? Canned reference oscillators
most often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be
corrected,
850mV peak to peak is 425mV peak voltage. Average of that is
0.425x0.636 =
0.27V. Average power is average volts squared divided by the
load impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I
can find it, that is, as PDF manuals are a nightmare to
navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that
it makes much difference in practice. it does seem a bit on the
low side, but despite reading through the most likely sources
(the service manual and the trouble-shooting/repair manual) I can
find nothing stated for what that signal level should be! This
may be due to the user-unfriendliness of very large PDF manuals;
I just don't know. Anyway, not very satisfactory! Later today I
plan to do a direct power meter measurement of the ref osc (since
none of us here seem to agree on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope
why not measure the peak to peak voltage on the scope and power on
the power meter and see which calculation 0.636 vs 0.707 gives the
closest agreement?
It wouldn't prove anything one way or ther other, though, since that
power meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be
accurate enough to meaningfully test your otherwise fine suggestion.
The 0 to +10 dBm range I mentioned came from the service manual.
Looking at your scope picture, it looks like a 3 Vpp signal, which
is +13 dBm, a very common distribution level, but one that exceeds
the analyzer's allowed range. All that's needed to fix this is a
.<https://www.amazon.com/MWRF-Source-Male-Female-Attenuator/dp/
B07MP9D9GC?th=1>
Post by Joe Gwinn
Just buying a few of these and doing some experiments will be far
cheaper and faster than the various alternatives discussed.t
Joe Gwinn
I think you're looking at the first picture with the signal into the
scope's 1 Meg input. The 50 ohm trace is only 850mV peak-to-peak or
thereabouts and when I measured it with an actual power meter, came
out at about +2.5dBm so within the range you stated; no attenuation
needed (thanks for the range, by the way; I needed to know that).
What we don't know is exactly how you made the various measurements.
If you are observing the signal from the 10 MHz reference where it
enters the analyzer, I would expect that there is a T-connector with
the scope (set to 1 Mohm) listening in to passing signals.
You also still appear to think that the 10Mhz signal is going into the
I did read that, but didn't know what to make of it. I think an
annotated drawing is required.
On this drawing, where do the various scope traces mentioned up-thread
come from?
Joe Gwinn
Post by Cursitor Doom
Post by Joe Gwinn
In this case, the load seen by the incoming reference is that provided
by the input on the analyzer. Which input is +10 dBm max. If you set
the observing scope input to 50 ohm, the reference will see a 25 ohm
load, cutting the signal seen by the analyzer by 3 dB. Which will
take +13 dBm down to +10 dBm, which is in range.
A 3dB attenuator in line will drop the signal to 10 dBm as well.
I've built lots of systems like that. The 10 MHz reference is
delivered to everybody at +13 dBm, and it is the receivers'
responsibility to attenuate it to whatever they need.
Post by Joe Gwinn
I've now measured the 100Mhz oscillator and that seems fine, although
I only saw 0.61V p-p into 50 ohms, so somewhat less than the 10Mhz
oscillator's output.
So far, I've not measured anything which screams "the fault's here!"
as all the expected signals are present - although admittedly I have
many more to test. But certainly all the *major* signals within this
complex beast are present. It's looking like it could be an issue with
one of the phase detectors or LPFs. Sigh....
To my eye, it does scream.
Joe Gwinn
Joe, I appreciate you're only trying to help, but don't worry about it. I
don't believe the oscillator this thread relates to is causing the PLL
unlock error so we've all gone down a bit of a rabbit hole with this one.
I really need to look elsewhere for the culprit.
For what it's worth, I found a manual on the web saying that the
10MHz output should deliver +5dBm into 50 Ohms. It's a bit low,
then, but I doubt that this is your problem.

Jeroen Belleman
Cursitor Doom
2024-06-03 17:53:50 UTC
Permalink
Post by Cursitor Doom
Post by Joe Gwinn
On Sun, 2 Jun 2024 20:58:45 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by Joe Gwinn
On Sun, 2 Jun 2024 16:55:28 -0000 (UTC), Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
On Sun, 2 Jun 2024 11:31:33 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input.
It's around 850mV peak-peak. Hopefully the slight
distortion I spoke about is visible; the slightly more
leisurely negative-going excursions WRT their
positive-going counterparts. So it's not a pure sine wave
as one would expect. Does it matter? I don't know!
<https://disk.yandex.com/i/7cuuBimDbOIBZw>
And <https://disk.yandex.com/i/z6fYbeVfPRK7aA>
Post by Cursitor Doom
Post by Joe Gwinn
Post by Joe Gwinn
Post by Joe Gwinn
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
The shape looks perfectly acceptable to me. This is +3dBm
into 50 Ohms.
Is that what it's supposed to be? Canned reference
oscillators most often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to
be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is
0.425x0.636 =
0.27V. Average power is average volts squared divided by the
load impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I
can find it, that is, as PDF manuals are a nightmare to
navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or
+2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power"
strictly speaking IIRC, so that's why I took the average
figure; not that it makes much difference in practice. it does
seem a bit on the low side, but despite reading through the
most likely sources (the service manual and the
trouble-shooting/repair manual) I can find nothing stated for
what that signal level should be! This may be due to the
user-unfriendliness of very large PDF manuals; I just don't
know. Anyway, not very satisfactory! Later today I plan to do a
direct power meter measurement of the ref osc (since none of us
here seem to agree on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an
oscilloscope why not measure the peak to peak voltage on the
scope and power on the power meter and see which calculation
0.636 vs 0.707 gives the closest agreement?
It wouldn't prove anything one way or ther other, though, since
that power meter hasn't been calibrated for "quite a while" so to
speak. :)
It'll give a 'good enough' reading for my purposes, but won't be
accurate enough to meaningfully test your otherwise fine suggestion.
The 0 to +10 dBm range I mentioned came from the service manual.
Looking at your scope picture, it looks like a 3 Vpp signal, which
is +13 dBm, a very common distribution level, but one that exceeds
the analyzer's allowed range. All that's needed to fix this is a
.<https://www.amazon.com/MWRF-Source-Male-Female-Attenuator/dp/
B07MP9D9GC?th=1>
Post by Joe Gwinn
Just buying a few of these and doing some experiments will be far
cheaper and faster than the various alternatives discussed.t
Joe Gwinn
I think you're looking at the first picture with the signal into
the scope's 1 Meg input. The 50 ohm trace is only 850mV
peak-to-peak or thereabouts and when I measured it with an actual
power meter, came out at about +2.5dBm so within the range you
stated; no attenuation needed (thanks for the range, by the way; I
needed to know that).
What we don't know is exactly how you made the various measurements.
If you are observing the signal from the 10 MHz reference where it
enters the analyzer, I would expect that there is a T-connector with
the scope (set to 1 Mohm) listening in to passing signals.
You also still appear to think that the 10Mhz signal is going into
I did read that, but didn't know what to make of it. I think an
annotated drawing is required.
On this drawing, where do the various scope traces mentioned up-thread
come from?
Joe Gwinn
Post by Cursitor Doom
Post by Joe Gwinn
In this case, the load seen by the incoming reference is that
provided by the input on the analyzer. Which input is +10 dBm max.
If you set the observing scope input to 50 ohm, the reference will
see a 25 ohm load, cutting the signal seen by the analyzer by 3 dB.
Which will take +13 dBm down to +10 dBm, which is in range.
A 3dB attenuator in line will drop the signal to 10 dBm as well.
I've built lots of systems like that. The 10 MHz reference is
delivered to everybody at +13 dBm, and it is the receivers'
responsibility to attenuate it to whatever they need.
Post by Joe Gwinn
I've now measured the 100Mhz oscillator and that seems fine,
although I only saw 0.61V p-p into 50 ohms, so somewhat less than
the 10Mhz oscillator's output.
So far, I've not measured anything which screams "the fault's
here!" as all the expected signals are present - although
admittedly I have many more to test. But certainly all the *major*
signals within this complex beast are present. It's looking like it
could be an issue with one of the phase detectors or LPFs. Sigh....
To my eye, it does scream.
Joe Gwinn
Joe, I appreciate you're only trying to help, but don't worry about it.
I don't believe the oscillator this thread relates to is causing the
PLL unlock error so we've all gone down a bit of a rabbit hole with
this one.
I really need to look elsewhere for the culprit.
For what it's worth, I found a manual on the web saying that the 10MHz
output should deliver +5dBm into 50 Ohms. It's a bit low, then, but I
doubt that this is your problem.
Jeroen Belleman
Thanks, Jeroen. It would be a pretty simple matter to provide the analyzer
with an external 10Mhz source of that level from an RF signal generator,
but as we've both said now, I don't think that's the issue.
The service manual only says to investigate boards A19,A20,A21 and A11 -
which I have done superficially. But I've just noticed in the Repair &
Troubleshooting manual it says A16 should also be checked, so I'll do that
next.....
Many thanks.
Jeroen Belleman
2024-06-02 18:18:50 UTC
Permalink
Post by Joe Gwinn
On Sun, 2 Jun 2024 11:31:33 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find
it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that it
makes much difference in practice. it does seem a bit on the low side,
but despite reading through the most likely sources (the service manual
and the trouble-shooting/repair manual) I can find nothing stated for
what that signal level should be! This may be due to the
user-unfriendliness of very large PDF manuals; I just don't know.
Anyway, not very satisfactory! Later today I plan to do a direct power
meter measurement of the ref osc (since none of us here seem to agree
on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope why
not measure the peak to peak voltage on the scope and power on the power
meter and see which calculation 0.636 vs 0.707 gives the closest
agreement?
It wouldn't prove anything one way or ther other, though, since that power
meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be accurate
enough to meaningfully test your otherwise fine suggestion.
The 0 to +10 dBm range I mentioned came from the service manual.
Looking at your scope picture, it looks like a 3 Vpp signal, which is
+13 dBm, a very common distribution level, but one that exceeds the
analyzer's allowed range. All that's needed to fix this is a 3dB
.<https://www.amazon.com/MWRF-Source-Male-Female-Attenuator/dp/B07MP9D9GC?th=1>
Just buying a few of these and doing some experiments will be far
cheaper and faster than the various alternatives discussed.
Joe Gwinn
What scope picture are you looking at? I see only 0.88Vpp.

Jeroen Belleman
Joe Gwinn
2024-06-02 19:44:31 UTC
Permalink
On Sun, 2 Jun 2024 20:18:50 +0200, Jeroen Belleman
Post by Jeroen Belleman
Post by Joe Gwinn
On Sun, 2 Jun 2024 11:31:33 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find
it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that it
makes much difference in practice. it does seem a bit on the low side,
but despite reading through the most likely sources (the service manual
and the trouble-shooting/repair manual) I can find nothing stated for
what that signal level should be! This may be due to the
user-unfriendliness of very large PDF manuals; I just don't know.
Anyway, not very satisfactory! Later today I plan to do a direct power
meter measurement of the ref osc (since none of us here seem to agree
on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope why
not measure the peak to peak voltage on the scope and power on the power
meter and see which calculation 0.636 vs 0.707 gives the closest
agreement?
It wouldn't prove anything one way or ther other, though, since that power
meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be accurate
enough to meaningfully test your otherwise fine suggestion.
The 0 to +10 dBm range I mentioned came from the service manual.
Looking at your scope picture, it looks like a 3 Vpp signal, which is
+13 dBm, a very common distribution level, but one that exceeds the
analyzer's allowed range. All that's needed to fix this is a 3dB
.<https://www.amazon.com/MWRF-Source-Male-Female-Attenuator/dp/B07MP9D9GC?th=1>
Just buying a few of these and doing some experiments will be far
cheaper and faster than the various alternatives discussed.
Joe Gwinn
What scope picture are you looking at? I see only 0.88Vpp.
This one, posted by CD on 1 June '24:

.< https://disk.yandex.com/i/7cuuBimDbOIBZw>

This is the one with the funny stuff at the bottom. If you look at
the upper waveshape, the peak amplitude to the inflection point near
the bottom is about 1.5 Vp, which implies 3 Vpp, which is +13 dBm into
50 ohms. Why the inflection point? Because in a undistorted sine
wave, the zero crossing is linear, and does not flair. The scope
picture does not show where zero volts is, so had to use the
inflection point.

Joe Gwinn
Jeroen Belleman
2024-06-02 21:45:43 UTC
Permalink
Post by Joe Gwinn
On Sun, 2 Jun 2024 20:18:50 +0200, Jeroen Belleman
Post by Jeroen Belleman
Post by Joe Gwinn
On Sun, 2 Jun 2024 11:31:33 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find
it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that it
makes much difference in practice. it does seem a bit on the low side,
but despite reading through the most likely sources (the service manual
and the trouble-shooting/repair manual) I can find nothing stated for
what that signal level should be! This may be due to the
user-unfriendliness of very large PDF manuals; I just don't know.
Anyway, not very satisfactory! Later today I plan to do a direct power
meter measurement of the ref osc (since none of us here seem to agree
on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope why
not measure the peak to peak voltage on the scope and power on the power
meter and see which calculation 0.636 vs 0.707 gives the closest
agreement?
It wouldn't prove anything one way or ther other, though, since that power
meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be accurate
enough to meaningfully test your otherwise fine suggestion.
The 0 to +10 dBm range I mentioned came from the service manual.
Looking at your scope picture, it looks like a 3 Vpp signal, which is
+13 dBm, a very common distribution level, but one that exceeds the
analyzer's allowed range. All that's needed to fix this is a 3dB
.<https://www.amazon.com/MWRF-Source-Male-Female-Attenuator/dp/B07MP9D9GC?th=1>
Just buying a few of these and doing some experiments will be far
cheaper and faster than the various alternatives discussed.
Joe Gwinn
What scope picture are you looking at? I see only 0.88Vpp.
.< https://disk.yandex.com/i/7cuuBimDbOIBZw>
This is the one with the funny stuff at the bottom. If you look at
the upper waveshape, the peak amplitude to the inflection point near
the bottom is about 1.5 Vp, which implies 3 Vpp, which is +13 dBm into
50 ohms. Why the inflection point? Because in a undistorted sine
wave, the zero crossing is linear, and does not flair. The scope
picture does not show where zero volts is, so had to use the
inflection point.
Joe Gwinn
I'm afraid you have lost me there... I see only a roughly
sine-shaped wave framed with cursors along the peaks being
0.88V apart. I don't care about the DC level, only the 10MHz
component matters. Its amplitude is only 0.44V.

Jeroen Belleman
Joe Gwinn
2024-06-03 11:43:41 UTC
Permalink
On Sun, 2 Jun 2024 23:45:43 +0200, Jeroen Belleman
Post by Jeroen Belleman
Post by Joe Gwinn
On Sun, 2 Jun 2024 20:18:50 +0200, Jeroen Belleman
Post by Jeroen Belleman
Post by Joe Gwinn
On Sun, 2 Jun 2024 11:31:33 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by piglet
Post by Cursitor Doom
Post by Jeroen Belleman
Post by Cursitor Doom
I've taken a shot of the waveform into the 50 ohm input. It's
around 850mV peak-peak. Hopefully the slight distortion I spoke
about is visible; the slightly more leisurely negative-going
excursions WRT their positive-going counterparts. So it's not a
pure sine wave as one would expect. Does it matter? I don't know!
https://disk.yandex.com/i/7cuuBimDbOIBZw
The shape looks perfectly acceptable to me. This is +3dBm into 50 Ohms.
Is that what it's supposed to be? Canned reference oscillators most
often deliver +13dBm, sometimes +10dBm.
Is it? I only make it about half your figure: +1.65dBm.
I admit I'm frequently prone to careless errors, so stand to be corrected,
850mV peak to peak is 425mV peak voltage. Average of that is 0.425x0.636 =
0.27V. Average power is average volts squared divided by the load
impedance of 50 ohms = 1.46mW = +1.65dBm.
I shall consult the manual to see what it ought to be - if I can find
it, that is, as PDF manuals are a nightmare to navigate IME.
Use 0.71 for RMS instead of 0.636 ! I make that about 1.8mW or +2.6dBm ?
Thanks, Erich. But there's no such thing as "RMS power" strictly
speaking IIRC, so that's why I took the average figure; not that it
makes much difference in practice. it does seem a bit on the low side,
but despite reading through the most likely sources (the service manual
and the trouble-shooting/repair manual) I can find nothing stated for
what that signal level should be! This may be due to the
user-unfriendliness of very large PDF manuals; I just don't know.
Anyway, not very satisfactory! Later today I plan to do a direct power
meter measurement of the ref osc (since none of us here seem to agree
on what 850mV vs 50 ohms equates to!!)
Since you have a power meter, a signal source, and an oscilloscope why
not measure the peak to peak voltage on the scope and power on the power
meter and see which calculation 0.636 vs 0.707 gives the closest
agreement?
It wouldn't prove anything one way or ther other, though, since that power
meter hasn't been calibrated for "quite a while" so to speak. :)
It'll give a 'good enough' reading for my purposes, but won't be accurate
enough to meaningfully test your otherwise fine suggestion.
The 0 to +10 dBm range I mentioned came from the service manual.
Looking at your scope picture, it looks like a 3 Vpp signal, which is
+13 dBm, a very common distribution level, but one that exceeds the
analyzer's allowed range. All that's needed to fix this is a 3dB
.<https://www.amazon.com/MWRF-Source-Male-Female-Attenuator/dp/B07MP9D9GC?th=1>
Just buying a few of these and doing some experiments will be far
cheaper and faster than the various alternatives discussed.
Joe Gwinn
What scope picture are you looking at? I see only 0.88Vpp.
.< https://disk.yandex.com/i/7cuuBimDbOIBZw>
This is the one with the funny stuff at the bottom. If you look at
the upper waveshape, the peak amplitude to the inflection point near
the bottom is about 1.5 Vp, which implies 3 Vpp, which is +13 dBm into
50 ohms. Why the inflection point? Because in a undistorted sine
wave, the zero crossing is linear, and does not flair. The scope
picture does not show where zero volts is, so had to use the
inflection point.
Joe Gwinn
I'm afraid you have lost me there... I see only a roughly
sine-shaped wave framed with cursors along the peaks being
0.88V apart. I don't care about the DC level, only the 10MHz
component matters. Its amplitude is only 0.44V.
I copied the wrong yandex.

Try this (29 May 2024):
.<https://disk.yandex.com/i/z6fYbeVfPRK7aA >

Joe Gwinn
boB
2024-05-30 01:19:40 UTC
Permalink
On Wed, 29 May 2024 20:49:27 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
Post by john larkin
Our boxes output a 10 MHz square wave. Our clock inputs have a 10 MHz
bandpass filter, so they accept most anything.
Weird but I'm not surprised that 4 feet if coax, unloaded at 10 MHz
gives a strange waveform. Can simulate this, I believe, in LTspice
using the transmission line element(s).

Learned something here though.

boB
AZ
john larkin
2024-05-30 03:08:58 UTC
Permalink
Post by Joe Gwinn
On Wed, 29 May 2024 20:49:27 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
Post by john larkin
Our boxes output a 10 MHz square wave. Our clock inputs have a 10 MHz
bandpass filter, so they accept most anything.
Weird but I'm not surprised that 4 feet if coax, unloaded at 10 MHz
gives a strange waveform. Can simulate this, I believe, in LTspice
using the transmission line element(s).
Learned something here though.
boB
AZ
No txline can create frequency components that are not in the source.

(Well, a NLTL can, but 4 feet of coax isn't a shock line.)

But the problem, as usual, is underspecified. Maybe some driver is
going nonlinear. A schematic would help.
boB
2024-05-30 18:55:55 UTC
Permalink
Post by john larkin
Post by Joe Gwinn
On Wed, 29 May 2024 20:49:27 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
Post by john larkin
Our boxes output a 10 MHz square wave. Our clock inputs have a 10 MHz
bandpass filter, so they accept most anything.
Weird but I'm not surprised that 4 feet if coax, unloaded at 10 MHz
gives a strange waveform. Can simulate this, I believe, in LTspice
using the transmission line element(s).
Learned something here though.
boB
AZ
No txline can create frequency components that are not in the source.
(Well, a NLTL can, but 4 feet of coax isn't a shock line.)
But the problem, as usual, is underspecified. Maybe some driver is
going nonlinear. A schematic would help.
I was thinking the same thing. Non-linearity.

But he said that when he loaded it with 50 Ohms, it went back to a
sinewave. Maybe that non-linearity went away when it was loaded ?
Could be some kind of termination non-linearity or even coming from
the source with the higher levels of reflections. Can't explain it
otherwise.

boB
Cursitor Doom
2024-06-02 17:39:45 UTC
Permalink
Post by Joe Gwinn
On Wed, 29 May 2024 20:49:27 -0000 (UTC), Cursitor Doom
Post by Cursitor Doom
Post by john larkin
On Wed, 29 May 2024 21:43:54 +0200, Arie de Muijnck
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found
the 10Mhz reference oscillator is generating an 'unsatisfactory
waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators
I was building and in the process of trying to iron out the wrinkles
of and certainly NOT a critical reference oscillator from a
respected manufacturer. Can anyone tell what's most likely going on
here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe
cable's only 4' long! However, with the 50 ohm input enabled, the 2nd
harmonic disappears. It's just one of those inexplicable mysteries that
no one knows the answer to. :)
Post by john larkin
Our boxes output a 10 MHz square wave. Our clock inputs have a 10 MHz
bandpass filter, so they accept most anything.
Weird but I'm not surprised that 4 feet if coax, unloaded at 10 MHz
gives a strange waveform. Can simulate this, I believe, in LTspice
using the transmission line element(s).
Learned something here though.
e
I'm guessing there should have been a 50 ohm load screwed into the rear
10Mhz reference oscillator output BNC socket when the analyzer's in use.
There wasn't one but there is now. Unfortunately it hasn't cleared the PLL
unlock issue.
Lasse Langwadt
2024-05-30 18:56:41 UTC
Permalink
Post by Cursitor Doom
Post by john larkin
Post by Arie de Muijnck
Post by Cursitor Doom
Gentlemen,
Whilst fault-finding on my HP 8566B spectrum analyzer, I've found the
10Mhz reference oscillator is generating an 'unsatisfactory waveform'
which may be causing the device to be unable to lock it's main PLL.
I've come across this waveshape before, but mostly with oscillators I
was building and in the process of trying to iron out the wrinkles of
and certainly NOT a critical reference oscillator from a respected
manufacturer. Can anyone tell what's most likely going on here?
https://disk.yandex.com/i/z6fYbeVfPRK7aA
Looks like reflections in the cable. Try the 50 Ohm termination.
Arie
If the drive is a sine wave, a cable can't generate that 2nd harmonic.
I don't understand how a reflection can account for it either. THe cable's
only 4' long! However, with the 50 ohm input enabled, the 2nd harmonic
disappears. It's just one of those inexplicable mysteries that no one
knows the answer to. :)
maybe the oscillator is source only so without a 50R load there's no
sink to do the low side of the sine
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